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Dmitry [639]
3 years ago
11

Which of the following determined that cathode rays are negatively charged?

Physics
1 answer:
andrew11 [14]3 years ago
6 0
D. J.J. Thomson is your answer
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A unit mass of an ideal gas at temperature T undergoes a reversible isothermal process from pressure P1 to pressure P2 while los
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Answer:

Option B

Change in entropy of the process is \Delta S= Rln(\frac{P_{1}}{P_{2}})

Explanation:

The entropy of a system is a measure of the degree of disorderliness of the system.

The entropy of a system moving from process 1 to 2 is given as

\Delta S = \int\limits^2_1 {\frac{\delta q}{T}}

recall from first law, \delta q =du +Pdv

hence we have, \Delta S = \int\limits^2_1 {\frac{du +Pdv}{T}}

since the process is isothermal, du= 0

this gives us \Delta S = \int\limits^2_1 {\frac{Pdv}{T}}

integrating within the limits of 1 and 2, will give us

\Delta S = R ln (\frac{V_{2}}{V_{1}})

also from ideal gas laws,

\frac{V_{2}}{V_{1}}=\frac{P_{1}}{P_{2}}

hence we have    \Delta S = R ln (\frac{P_{1}}{P_{2}})

This makes the correct option B

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