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2 years ago

1. 20.0 mL of a liquid has a mass of 58.2 g. What is the density of the liquid?

Physics

2 answers:

skelet666 [1.2K]2 years ago

7 0

Answer:

use the formula mass over volume

podryga [215]2 years ago

6 0

D=M/V
D=58.2/20.0
D=2.91

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When an electromagnetic wave falls on a white, perfectly reflectingsurface, it exerts a force F on that surface. If the surfacei

Svetlanka [38]

Answer:

B. F/2

Explanation:

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2 years ago

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3 years ago

Two narrow slits 0.02 mm apart are illuminated by light from a CuAr laser (λ = 633 nm) onto a screen. a) If the first fringe is

Masja [62]

Answer:

a) 0.063m

b) 2.72°

c) 3151 fringes

d) 1.87*10^-6m

Explanation:

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$y=\frac{m\lambda D}{d}\\\\D=\frac{dy}{m\lambda}$

D: screen distance

d: distance between slits

m: order of the fringes

λ: wavelength

By replacing the values of the parameters you obtain:

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b) The condition for dark fringes is given by:

$\lambda(m+\frac{1}{2})=dsin\theta$

for the first dark fringe the angle is:

$\theta=sin^{-1}(\frac{\lambda(m+\frac{1}{2})}{d})\\\\\theta=sin^{-1}(\frac{(633*10^{-9}m)(1+\frac{1}{2})}{0.02*10^{-3}m})=2.72\°$

c) the visible number of fringes is given by:

$N=1+2\frac{D}{d}=1+\frac{0.063m}{0.02*10^{-3}}=3151 \ fringes$

d) the wavelength of a laser in which its first order fringe coincides with the third one of the CuAr laser is:

$y=\frac{(3)(633*10^{-9}m)(0.063m)}{0.02*10^{-3}m}=5.98*10^{-3}m\approx0.59cm\\\\\lambda'=\frac{dy}{mD}=\frac{(0.02*10^{-3}m)(0.59*10^{-2}m)}{(1)(0.063m)}=1.87*10^{-6}m$

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2 years ago

7. Who provided evidence for the existence of an atomic nucleus?

andreyandreev [35.5K]

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Explanation:

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2 years ago

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Kisachek [45]

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