Answer:

Explanation:
From this exercise, our knowable variables are <u>hight and initial velocity </u>


To find how much time does the <u>ball strike the ground</u>, we need to know that the final position of the ball is y=0ft


Solving for t using quadratic formula


or 
<u><em>Since time can't be negative the answer is t=6.96s</em></u>
Magnitude of normal force acting on the block is 7 N
Explanation:
10N = 1.02kg
Mass of the block = m = 1.02 kg
Angle of incline Θ
= 30°
Normal force acting on the block = N
From the free body diagram,
N = mgCos Θ
N = (1.02)(9.81)Cos(30)
N = 8.66 N
Rounding off to nearest whole number,
N = 7 N
Magnitude of normal force acting on the block = 7 N
add the numbers from the three sliders to determine that mass of an object
Answer:
100 cc
Explanation:
Heat released in cooling human body by t degree
= mass of the body x specific heat of the body x t
Substituting the data given
Heat released by the body
= 70 x 3480 x 1
= 243600 J
Mass of water to be evaporated
= 243600 / latent heat of vaporization of water
= 243600 / 2420000
= .1 kg
= 100 g
volume of water
= mass / density
= 100 / 1
100 cc
1 / 10 litres.
Answer:
alpha=53.56rad/s
a=5784rad/s^2
Explanation:
First of all, we have to compute the time in which point D has a velocity of v=23ft/s (v0=0ft/s)

Now, we can calculate the angular acceleration (w0=0rad/s)


with this value we can compute the angular velocity

and the tangential velocity of point B, and then the acceleration of point B:

hope this helps!!