Answer:
3.3535 g
Explanation:
Considering:
Or,
Given :
For iron(III) nitrate :
Molarity = 0.404 M
Volume = 52.0 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 52.0×10⁻³ L
Thus, moles of iron(III) nitrate :
Moles of iron(III) nitrate = 0.021 moles
1 mole of iron(III) nitrate forms 1 mole of iron(III) hydroxide which further forms 1 mole of iron(III) oxide.
Thus, moles of iron(III) oxide formed from 0.021 moles of iron(III) nitrate = 0.021 moles
Also, molar mass of iron(III) oxide = 159.69 g/mol
So, mass of iron(III) oxide = 0.021 moles × 159.69 g/mol = 3.3535 g
Answer:
1)grams 2) cubic centimeters 3) grams/cubic centimeters
Explanation:
I just put it in <3
When 2-pentanol gets oxidized you end up with 2-pentanone. In this case, since we are oxidizing a secondary alcohol you end up with a ketone. They cannot be oxidized further than that. If it was a primary alcohol you would end up with an aldehyde.
You can find the mechanism as well the molecule formula of both 2pentanol and 2pentanone attached.
Answer:
10.76 grams
Explanation:
Given that the amount of 
is 25.0 grams.
Mass of 1 mole of = 158 grams
The number of atoms in 1 mole of is 4.
Mass of oxygen in 1 mole of = 16\times 4 = 68 grams.
Here, 158 grams of has 68 grams of oxygen
So, the amount of oxygen in 1 gram of = 68/158 grams
Therefore, the amount of oxygen in 1 gram of = 
grams
=10.76 grams
Hence, 25 grams of has 10.76 grams of oxygen.
Answer:
Ethyl Methanoate H-CO2-CH2-CH3 Rum
Explanation:
