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katrin [286]
3 years ago
14

What if the solubility of KNO3 at 60 celsius?

Chemistry
1 answer:
Liula [17]3 years ago
8 0

Answer:

D. 108 grams of KNO3(Potassium nitrate)

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You are running a lemonade stand with your friend. You prepared 10 liters of 0.7 molarity lemonade, but your friend did online r
olga nikolaevna [1]

Answer:

add 7.5L of water

Explanation:

M1×V1=M2×V2

M is molarity, V is volume

0.7 × 10 = 0.4 × V2

V2= 17.5L

vol. of water to add= 17.5 - 10 = 7.5L

3 0
3 years ago
A 111.6 gram sample of iron (MW=55.8) was heated from 0 degrees C to 20 degrees C. It absorbed 1004 Joules of energy. What is th
qwelly [4]
Use the equation q=ncΔT.
q= heat absorbed our released (in this case 1004J)
n= number of moles of sample ( in this case 2.08 mol)
c=molar heat capacity 
ΔT=change in temperature (in this case 20°C)
You have to rewrite the equation for c.
c=q/nΔT
c=1004J/(2.08mol x 20°C)
c=24.1 J/mol°C
 
I hope this helps
7 0
3 years ago
Calculate the Ph and the POH of an aqueous solution that is 0. 040 m in HCl(aq) and 0. 075 m in HBr(aq) at 25 °C.
LenaWriter [7]

pH is the measure of the hydrogen ion concentration while pOH is of hydroxide ion concentration in the solution. The pH is 0.939 and pOH is 13.061 pOH.

pH is the concentration of the hydrogen ion released or gained by the species in the solution that depicts the acidity and basicity of the solution.

pOH is the concentration of the hydroxide ion in the solution and is dependent on the pH as an increase in pH decreases the pOH and vice versa.

Both HCl and HBr are strong acids and gets ionized 100 % in the solution. If we let 1 L of solution for the acids then the concentration of the hydrogen ion will be 0.100 M.

Since both completely dissociate we would just add the molarities of each of the H+ ions together and then calculate the PH and POH from that :

HCL(0.040M)----> H+(0.040M) +CL-(0.040M)

HBr(0.075M)----> H+(0.075M) +Br-(0.075M)

so 0.040M (H+ from HCL) + 0.075M (H+ from HBr) = 0.115M H+ in total.

pH is calculated as:

pH = -log[H+]

Substituting values in the equation:

log(0.115M)= 0.939 pH

pOH is calculated as:

14 - pH = pOH

Substituting values in the equation above:

14 - 0.939= 13.061 pOH

Therefore, pH is 0.939 and pOH is 13.061.

Learn more about pH and pOH here:

brainly.com/question/2947041

#SPJ4

5 0
2 years ago
1) If the pressure on 2.6 liters of a gas at 860 Torr is increased to 1000 Torr,
LenKa [72]

2.24 liters is the volume of the gas if pressure is increased to 1000 Torr.

Explanation:

Data given:

Initial volume of the gas V1 = 2.6 liters

Initial pressure of the gas P1 = 860 Torr 1.13 atm

final pressure on the gas P2 = 1000 Torr 1.315 atm

final volume of the gas after pressure change V2 =?

From the data given above, the law used is :

Boyles Law equation:

P1V1 = P2V2

V2 = P1V1/P2

   = 1.13 X 2.6/ 1.31

  = 2.24 Liters

If the pressure is increased to 1000 Torr or 1.315 atm the volume changes to 2.24 liters. Initially the volume was 2.6 litres and the pressure was 860 torr.

6 0
3 years ago
Curium – 245 is an alpha emitter. Write the equation for the nuclear reaction and identify the product nucleus.
BabaBlast [244]

Answer:

Please find the complete solution in the attached file.

Explanation:

7 0
3 years ago
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