Question

(a) Design a low-pass filter with a cutoff frequency of 12 kHz. Use0.15 uF capacitor and an appropriate resistor. B) Sketch and label the circuit. C) What is the gain of the filter at a frequencyof 20 kHz? Give your answer both as ratio (Vout/Vin) and in dB

Answer 1

Answer:

A) 88.42 ohms

c) 0.5145 and - 5.77 db

Explanation:

A)  Value of cut-off frequency = 12 kHz

capacitance of capacitor =0.15 microF

formula for cut-off frequency of a low-pass filter

$Fc = \frac{1}{2\pi RC}$   making R the subject of the formula in other to get the resistance of the low pass filter resistor

R = $\frac{1}{2\pi (12*10^3)(0.15*10^{-6} )}$ = 88.42 OHMS

attached is the solution for B and C