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sasho [114]
3 years ago
7

What properties does a loud, shrill whistle have? a.) high amplitude, high frequency

Physics
1 answer:
marysya [2.9K]3 years ago
4 0

Answer:

a.) high amplitude, high frequency

Explanation:

Frequency and amplitude are properties of sound. Varying these properties changes how people perceive sound.

While hearing sound of a particular frequency we call it pitch i.e., the perception of a frequency of sound.

High pitch means high frequency and high frequency is perceived to have a shrill sound.

The loudness of a sound is measured by the intensity of sound i.e., the energy the sound possesses per unit area. As the amplitude increases the intensity increases. So, a loud sound will have higher density.

Hence, the loud shrill whistle will have high frequency and high amplitude.

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Identify which portions of the electromagnetic spectrum are used in each of the devices listed. a. a microwave oven b. a televis
dlinn [17]

The portions of the electromagnetic spectrum are used in the television set. It is used in the picture tube in the old television set.

<h3>What is the electromagnetic spectrum ?</h3>

The electromagnetic radiation distribution in accordance with the frequency or wavelength is known as the electromagnetic spectrum.

The portions of the electromagnetic spectrum are used in the television set. It is used in the picture tube in the old television set.

Hence, option b is correct.

To learn more about the electromagnetic spectrum, refer to the link;

brainly.com/question/15576247

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6 0
2 years ago
What particles of an atom are inside the neuculas?
Mrac [35]
*It's nucleas. There are protons, neutrons and electrons.
3 0
3 years ago
Mercury has a mass of 3.3 e 23 kg and a radius of 2.44 e 6 m. Find Mercury's
valentina_108 [34]

Answer:

11.) g = 3.695 m/s^2

12.) g = 8.879 m/s^2

13.) E = 8127 N/C

Explanation:

11.) Given that the

Mercury mass M = 3.3 × 10^23kg

Radius r = 2.44 ×10^6 m

Gravitational constant G = 6.67408 × 10^-11 m3kg-1 s^-2

Gravitational field strength g can be calculated by using the formula below

g = GM/r^2

Substitutes all the parameters into the formula

g = (6.67408 × 10^-11 × 3.3 × 10^23)/(2.44×10^6)^2

g = 2.2×10^13/5.954×10^12

g = 3.695 m/s^2

12.) Given that the

Venus mass M = 4.87×10^24kg

Radius r = 6.05 × 10^6 m

Using the same formula for gravitational field strength g

g = GM/R2

Substitute all the parameters into the formula

g = (6.67408 × 10^-11 × 4.87×10^24)/(6.05×10^6)^2

g = 3.25×10^14/3.66×10^13

g = 8.879 m/s^2

13.) Given that the

Charge = 2.26 nC = 2.26×10^-9

Distance d = 0.05m

Electric field strength E can be calculated by using the formula below

E = Kq/d^2

Where

K = electrostatic constant 8.99 × 10^9 Nm2/C2

Substitutes all the parameters into the formula

E = (8.99 × 10^9 × 2.26×10^-9)/0.05^2

E = 20.3174/2.5×10^-3

E = 8126.96 N/C

7 0
4 years ago
What happens to the amount of energy present when it is moved from one form to another
Jet001 [13]
The amount of energy is ALWAYS conserved based on the law of conservation of energy. Therefore, the amount of energy will remain the same. 
3 0
3 years ago
Calculate the air pressure in the pressurized tank, if h1 = 0. 18 m, h2 = 0. 2m and h3 = 0. 25m. The density of the mercury, wat
fomenos

The air pressure in the pressurized tank will be 24014.88 N/m²,196.2 N/m²,2084.625  N/m².

<h3 /><h3>What is pressure?</h3>

The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.

It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.

Pressure is found as the product of the density,acceleraton due to gravity and the height.

P₁=ρ₁gh₁

P₁=13,600 kg/m³×9.81 (m/s²)×0.18 m

P₁=24014.88 N/m²

P₂=ρ₂gh₂

P₂= 1000 kg/m³×9.81 (m/s²)×00.2 m

P₂=196.2 N/m²

P₃=ρ₃gh₃

P₃=850 kg/m³×9.81 (m/s²)×0.25

P₃=2084.625  N/m²

Hence,the air pressure in the pressurized tank will be 24014.88 N/m²,196.2 N/m²,2084.625  N/m².

To learn more about the pressure refer to the link;

brainly.com/question/356585

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6 0
2 years ago
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