The power is 833.3 W
Explanation:
First of all, we need to calculate the work done in lifting the barbell, which is equal to the change in gravitational potential energy of the barbell:
where
mg = 1250 N is the weight of the barbell
h = 2 m is the change in height
Substituting,
Now we can calculate the power, which is equal to the work done per unit time:
where
W = 2500 J is the work done
t = 3 s is the time taken
Substituting,
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By using the second law of Newton, the frictional force is 200N.
We need to know about the second law of Newton (force) to solve this problem. The total force applied an object is proportional to the mass of object and acceleration. It can be defined as
∑F = m . a
where F is force, m is mass and a is acceleration.
From the question above, we know that
F1 = 200N
v = constant therefore (a = 0 m/s²)
By using second law of Newton, we get
∑F = m . a
F1 - Ffriction = m . 0
200 - Ffriction = 0
Ffriction = 200 N
Hence, the frictional force is 200N.
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Answer:
like horror? or action haha
Explanation:
The value of spring constant and the oscillator's damping constant is
K= 6605.667008, b= 0.002884387
Explanation:
For Weakly damping spring oscillator
K/m = W_0^2 (at resonance)
K= mW_0^2
=0.206 * ( 2π * 28.5) ^2
=0.206 * (2π)^2 * (28.5)^2
K= 6605.667008
F = - bV
b= -F/V = -F/ -W_0 * m
=F/W_0 * m
= 0.438N / 2π * 28.5 * 0.848
b= 0.002884387
