Question

3. The molar volume of a gas at STP occupies 0 1 kilopascal O ooc 12 grams 22.4 L

Answer 1

The molar volume of a gas at STP occupies 22.4 L.

Option D

Explanation:

To find the volume of 1 mole of a gas at STP, we use the Ideal Gas Law. It is the general gas equation which gives the relation to the measurable quantities to an ideal gas as below,

P (pressure) × V (volume) = n (number of moles) × R (the gas constant) × T (temperature in Kelvin)

STP = 1 atm of pressure and 273 K for temperature

P = 1 atm

V = ?

n = 1 mole

R = 0.0821 atm L/mol K

T = 273 K

Using the equation,

$\mathrm{PV}=\mathrm{nRT}$

$V=\frac{n R T}{P}$

By substituting the above values, in the equation,

$V=\frac{1 \times 0.082 \times 273}{1}=22.38\ L$

V = 22.38 L