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sesenic [268]
3 years ago
7

Add 92.2 km to 9426 m and report the answer in

Chemistry
1 answer:
Mashcka [7]3 years ago
3 0

to convert m into km we have to divide it by 1000.so,

9426/1000=9.426km

92.2km+9.426km=101.626km.

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Which of these functional groups is found in all amino acids? -NH2 -OH =O -PO42-
melisa1 [442]

Answer : The correct option is, -NH_2

Explanation :

Amino acid : The acid that contains two functional groups that are carboxylic group, -COOH and ammine group, -NH_2.

When the two or more that two amino acids join together with the help of peptide bond, they produces polypeptide chain or protein.

The bond present between the two amino acid is called a peptide bond.

The peptide bond is a chemical bond that is formed between the two molecules when the nitrogen of one amino acid react with the carbon of another amino acid by releasing a water molecule. This is a dehydration synthesis or condensation reaction.

From this we conclude that, only two functional groups carboxylic group, -COOH and ammine group, -NH_2 are present in all amino acids.

Hence, the correct option is, -NH_2

7 0
3 years ago
Can someone label these?
STatiana [176]
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8 0
2 years ago
400 liters of a certain gas is collected at STP. What will the volume be at 273 C and 190 torr pressure?
Firlakuza [10]

Answer:

2.00 L of a gas is collected at 25.0°C and 745.0 mmHg. What is the volume at STP? STP is a common abbreviation for "standard temperature and pressure." You have to recognize that five values are given in the problem and the sixth is an x. Also ... 273 1. A gas has a volume of 800.0 mL at minus 23.00 °C and 300.0 torr.

Explanation:

3 0
3 years ago
How many electrons does the copper atom lose in the process: Cu → Cu3+ + ? electrons
alexdok [17]

Answer:

3

Explanation:

6 0
2 years ago
For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.43×10-4 /s and the
ladessa [460]

<span>Answer is: activation energy of this reaction is 212,01975 kJ/mol.
Arrhenius equation: ln(k</span>₁/k₂) = Ea/R (1/T₂ - 1/T₁<span>).
k</span>₁<span> = 0,000643 1/s.
k</span>₂ = 0,00828 1/s.

T₁ = 622 K.

T₂ = 666 K.

R = 8,3145 J/Kmol.

1/T₁<span> = 1/622 K = 0,0016 1/K.
1/T</span>₂<span> = 1/666 K = 0,0015 1/K.
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).
-2,55 = Ea/8,3145 J/Kmol · (-0,0001 1/K).
Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>

4 0
3 years ago
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