Hi sorry
I don’t know
but maybe next time
Answer:
A team of Chinese researchers have turned cheap copper into a new material “almost identical” to gold, according to a study published in peer-reviewed journal Science Advances on Saturday. The fast-moving ionized particles blasted copper atoms off the target.
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Explanation:
Answer:
1474.0 torr.
Explanation:
- To calculate the no. of moles of a gas, we can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant.
T is the temperature of the gas in K.
- If n is constant, and have two different values of (P, V and T):
<em>P₁V₁T₂ = P₂V₂T₁</em>
<em></em>
P₁ = 895.0 torr, V₁ = 8.8 L, T₁ = 25°C + 273 = 298 K.
P₂ = ??? torr, V₂ = 5.9 L, T₂ = 56°C + 273 = 329 K.
<em>∴ P₂ = P₁V₁T₂/V₂T₁</em> = (895.0 torr)(8.8 L)(329 K)/(5.9 L)(298 K) = <em>1474.0 torr.</em>
Answer:
A
Explanation:
A hydroxide ion is given as:
OH⁻
The electron dot notation shows only the chemical symbol of the element surrounded by dots to represent the valence electrons. The chemical symbol denotes the nucleus and all electrons except the valence electrons.
The dots are arranged on the four sides in pairs.
Oxygen is made up of 6 valence electrons, and since the ion has a net negative charge, the hydrogen and oxygen achieved their stable configuration this way.
Answer:
Na.
Explanation:
- The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
- An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. Also known as the electron acceptor, the oxidizing agent is normally in one of its higher possible oxidation states because it will gain electrons and be reduced.
- A reducing agent (also called a reductant or reducer) is an element (such as calcium) or compound that loses (or "donates") an electron to another chemical species in a redox chemical reaction.
<em>2Na + S → Na₂S.</em>
<em></em>
Na is oxidized to Na⁺ in (Na₂S) (loses 1 electron). "reducing agent".
S is reduced to S²⁻ in (Na₂S) (gains 2 electrons). "oxidizing agent".