Answer:
C.)house temperature increases cause the bimetallic coil to expand
Explanation:
A bimetallic strip is used in an air conditioner as a regulator. It is made up of two metals that behaves differently to a change in temperature.
To turn on the air conditoner, the circuit must be complete. When the temperature is high in a room, bimetallic strip responds by expanding and bending to complete the circuit. This puts on the air conditioner and the house begins to cool through exchange of warm and cold air.
When the temperature is too cold, the strip contracts and straightens. This process disconnects the circuit and the air conditioning system ceases to work.
Answer:
it is 90 km in one hour it is 90km/h
90/60=1,5
When the balanced equation for this reaction is:
2Fe + 3H2O → Fe2O3 + 3H2
and according to the vapour pressure formula:
PV= nRT
when we have P is the vapor pressure of H2O= 0.121 atm
and V is the volume of H2O = 4.5 L
and T in Kelvin = 52.5 +273 = 325.5 K
R= 0.08205 atm-L/g mol-K
So we can get n H2O
So, by substitution:
n H2O = PV/RT
= (0.121*4.5)/(0.08205 * 325.5) = 0.02038 gmol
n Fe2O3 = 0.02038 * (1Fe2O3/ 3H2O) = 0.00679 gmol
Note: we get (1FeO3/3H2O) ratio from the balanced equation.
we can get the Mass of Fe2O3 from this formula:
Mass = number of moles * molecular weight
when we have a molecular weight of Fe2O3 = 159.7
= 0.00679 * 159.7 = 1.084 g
∴ 1.084 gm of Fe2O3 will produced
Answer:

Explanation:
To solve this problem, we can use the Combined Gas Laws:

Data:
p₁ = 2.02 atm; V₁ = 736 mL; n₁ = n₁; T₁ = 1 °C
p₂ = ?; V₂ = 416 mL; n₂ = n₁; T₂ = 82 °C
Calculations:
(a) Convert the temperatures to kelvins
T₁ = ( 1 + 273.15) K = 274.15 K
T₂ = (82 + 273.15) K = 355.15 K
(b) Calculate the new pressure

The volume of NH₃ produced at STP : 0.237 L
<h3>Further explanation</h3>
Reaction
N₂ + 3H₂ → 2NH₃
1 mol = 6.02 x 10²³ particles
9.6 X 10²¹ molecules of Hydrogen, mol :

mol H₂ : mol NH₃ = 3 : 2
mol NH₃ :

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). <em>At STP, Vm is 22.4 liters/mol.</em>
The volume of NH₃ :

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