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2 years ago

Not sure how to write this question so I will add an image

Chemistry

2 answers:

galben [10]2 years ago

8 0

Explanation:

1) When phosphoric acid reacts with calcium hydroxide neutralization reaction takes place in which calcium phosphate is formed along with formation of water.

The balanced chemical equation is give as:

$2H_3PO_4+3Ca(OH)_2\rightarrow Ca_3(PO_4)_2+6H_2O$

2) When calcium oxide acid reacts with phosphorus pentoxide addition reaction takes place in which calcium phosphate is formed.

The balanced chemical equation is give as:

$3CaO+P_2O_5\rightarrow Ca_3(PO_4)_2$

Nonamiya [84]2 years ago

5 0

Answer:

2H3PO4 + 3Ca(OH)2 = Ca3(PO4)2 + 6H2O

3CaO + P2O5 = Ca3(PO4)2

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Name a Solid, Liquid, and a Gas. Solid: Liquid: Gas:

crimeas [40]

Answer:

Gas - Steam

Solid - Rock

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3 years ago

Read 2 more answers

The vapor pressure of ethanol is 30°C at 98.5 mmHg and the heat of vaporization is 39.3 kJ/mol. Determine the normal boiling poi

Gelneren [198K]

Answer : The normal boiling point of ethanol will be, $348.67K$ or $75.67^oC$

Explanation :

The Clausius- Clapeyron equation is :

$\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})$

where,

$P_1$ = vapor pressure of ethanol at $30^oC$ = 98.5 mmHg

$P_2$ = vapor pressure of ethanol at normal boiling point = 1 atm = 760 mmHg

$T_1$ = temperature of ethanol = $30^oC=273+30=303K$

$T_2$ = normal boiling point of ethanol = ?

$\Delta H_{vap}$ = heat of vaporization = 39.3 kJ/mole = 39300 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

$\ln (\frac{760mmHg}{98.5mmHg})=\frac{39300J/mole}{8.314J/K.mole}\times (\frac{1}{303K}-\frac{1}{T_2})$

$T_2=348.67K=348.67-273=75.67^oC$

Hence, the normal boiling point of ethanol will be, $348.67K$ or $75.67^oC$

3 0

3 years ago

Give the name (not formula) of the hydrocarbon

nordsb [41]

hydrocarbon is ethene which is used to test for saturation and it undergoes addition reaction

5 0

2 years ago

Earth Science

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2 years ago

Arrange the following in order of increasing bond strength of the carbon oxygen bond:

Brilliant_brown [7]

Answer:

The correct option is: Carbonate ion < Carbon dioxide < Carbon monoxide

Explanation:

Bond energy is defined as the average energy needed to break a chemical covalent bond and signifies the strength of chemical covalent bond.

The bond strength of a covalent bond depends upon the bond length and the bond order.

Carbon monoxide molecule (CO) has two covalent bond and one dative bond. Bond order 2.6

Carbon dioxide (CO₂) has two carbon-oxygen (C-O) double bonds of equal length. Bond order 2.0

Carbonate ion (CO₃²⁻) has three C-O partial double bonds. Bond order 1.5

Also, the bond length is inversely proportional to the bond order and bond strength.

Therefore, order of C-O bond length: Carbon monoxide<Carbon dioxide<Carbonate ion

Order of C-O bond order: Carbonate ion<Carbon dioxide<Carbon monoxide

Order of C-O bond strength or energy: Carbonate ion<Carbon dioxide<Carbon monoxide

7 0

3 years ago