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Andreyy89
3 years ago
10

You apply a force to a cart. The force that you apply is directed to the right. Assume that there is friction acting on the cart

in addition to your applied force. In what direction is the net frictional force (the sum of the only other forces, besides the one you apply, in the right/left directions)?
Physics
1 answer:
amid [387]3 years ago
4 0

Answer:

As we know that friction force always oppose the motion of body.In other words we can say that friction act opposite to the direction of motion of the body.It tries to stop the body is body is in motion.The value of friction force varies and reaches up to a maximum value.If the body is in rest condition then friction force will be static friction and the body is in moving position then the friction force will be kinetic friction.

Here given that we apply a force in the right direction then friction will act in the left direction.

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A pulley system has an efficiency of 74.2%. If you perform 200 J of work, how
Fudgin [204]

Answer:

C

Explanation:

If a pulley system has an efficiency of 74.2%, then only that fraction of the work performed will be useful. 74.2%=0.742. 0.742*200 is about 148J. Hope this helps!

8 0
2 years ago
If 710- nm and 660- nm light passes through two slits 0.65 mm apart, how far apart are the second-order fringes for these two wa
alexira [117]

0.23 mm far apart are the second-order fringes for these two wavelengths on a screen 1.5 m away.

<h3>Given wavelengths 710nm and 660nm,0.65mm apart two slits, and a screen 1.5m away.</h3>

Position of n the order fringe = n λ D / d

for n = 2

position = 2 λ D / d

λ = 710 nm , D = 1.5m

d = .65 x 10⁻³

position 1 = 2 x 710 x 10⁻⁹ x 1.5 / .65 x 10⁻³

= 3276.92 x 10⁻⁶ m

= 3.276x 10⁻³ m

= 3.276mm .

For λ = 660 nm

position = 2 λ D / d

λ = 660 nm , D = 1.5 m

d = .65 x 10⁻³

position 2 = 2 x 660 x 10⁻⁹ x 1.5 / .65 x 10⁻³

= 3046.15 x 10⁻⁶ m

= 3.046 x 10⁻³ m

= 3.046 mm .

Difference between their position

= 3.276mm ₋ 3.046 mm

= 0.23 mm .

To know more about Fringes refer to:  brainly.com/question/15649748

#SPJ4

7 0
1 year ago
A cook preparing a meal for a group of people is an example of
Fudgin [204]
Kinetic and potential energy he has the ability to make a meal and because he is making the meal

6 0
3 years ago
Calculate the force needed to bring a 1,019-kg car to rest from a speed of 29 m/s in a distance of 118 m
son4ous [18]
Acceleration = ▵v/▵t
Time = d/v
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Now the force.
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F= 1,019 * 7.25
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8 0
3 years ago
Match the phrase with the term. How hard the blood pushes on the inside of the blood vessels is called . The total amount of blo
taurus [48]

Answer:

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CARDIAC OUTPUT

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Explanation:

4 0
3 years ago
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