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lora16 [44]
3 years ago
14

Mercury is added to a cylindrical container to a depth d and then the rest of the cylinder is filled with water. If the cylinder

is 0.9 m tall and the absolute (or total) pressure at the bottom is 1.1 atmospheres, determine the depth of the mercury. (Assume the density of mercury to be 1.36 104 kg/m3, and the ambient atmospheric pressure to be 1.013e5 Pa)
Physics
1 answer:
V125BC [204]3 years ago
3 0

Answer:0.0106 m

Explanation:

Given

Absolute Pressure at the bottom is P=1.1 atm

Height of cylinder is h=0.9 m

Density of mercury \rho _{hg}=13.6\times 10^{3} kg/m^3

Pressure Difference is given by

\Delta P=\rho g\cdot h_0

Pressure at bottom=Pressure at Top+Pressure due to mercury and water

1.1\times 1.0132\times 10^5=1.01325\times 10^5+\rho _w\times 9.8\times (0.9-d)+\rho _{hg}\times 9.8\times d

converting Pressure into KPa

111.45=101.325+9.8\cdot (0.9-d)+13.6\cdot 9.8\cdot d

\frac{10.13}{9.8}=0.9 -d +13.6 d

d=0.0106 m

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