Answer:
The first part can be solved via conservation of energy.
For the second part,
the free body diagram of the car should be as follows:
- weight in the downwards direction
- normal force of the track to the car in the downwards direction
The total force should be equal to the centripetal force by Newton's Second Law.
where 
because we are looking for the case where the car loses contact.
Now we know the minimum velocity that the car should have. Using the energy conservation found in the first part, we can calculate the minimum height.
Explanation:
The point that might confuse you in this question is the direction of the normal force at the top of the loop.
We usually use the normal force opposite to the weight. However, normal force is the force that the road exerts on us. Imagine that the car goes through the loop very very fast. Its tires will feel a great amount of normal force, if its velocity is quite high. By the same logic, if its velocity is too low, it might not feel a normal force at all, which means losing contact with the track.
The correct answer for the question that is being presented above is this one: "c. transition state stage." During the transition state stage, the reaction of the atoms have the highest energy. It is also <span>during the formation of the activated complex in the middle of the experiment.</span>
The starting point for measuring motion is called : The Reference Point.
Answer:
Approaches mathematical learning through inquiry
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Explanation:
quizlet
Answer:
Explanation:
Given that,
Magnetic field of 0.24T
B = 0.24T
Field perpendicular to plane i.e 90°
Rate of decrease of length of side of square is 5.4cm/s
dL/dt = 5.4cm/s = 0.054m/s
Since it is decreasing
Then, dL/dt = -0.054m/s
When L is 14cm, what is the EMF induced?
L = 14cm = 0.14m
EMF is give as
ε = - dΦ/dt
Where flux is given as
Φ = BA
Where A is the area of the square
A = L²
Then, Φ = BL²
Substituting this into the EMF
ε = - dΦ/dt
ε = - d(BL²)/dt
B is constant
ε = - Bd(L²)/dt
ε = -2BL dL/dr
ε = -2 × 0.24 × 0.14 × -0.054
ε = 3.63 × 10^-3 V
ε = 3.63mV
