Normal reaction force on the block while it is at rest on the inclined plane is given as
here we know that
m = 46 kg
now we will have
now the limiting friction or maximum value of static friction on the block will be given as
Above value is the maximum value of force at which block will not slide
Now the weight of the block which is parallel to inclined plane is given as
here we know that
Now since the weight of the block here is less than the value of limiting friction force and also the block is at rest then the frictional force on the block is static friction and it will just counter balance the weight of the block along the inclined plane.
So here <u>friction force on the given block will be same as its component on weight which is 218.55 N</u>
Gases are easily compressed, the particles have large spaces between them, so it is easy to push them closer together. Gases have very low densities, there are huge amounts of space between particles. Due to the large spaces between particles in a gas you can force the particles closer together using a plunger.
A is false because light and sound waves can both reflect off of objects
-2. This is because it is gaining electrons. Electrons are negative. Therefore it is a negative charge.
Answer:
The developed pressure is 205.75 bar.
Explanation:
Given that,
Temperature of water =25°C = 273+25 = 298 K
Pressure = 1 bar
Increases temperature = 50°C = 273+50 = 323 K
Value of 
Value of 
Specific volume of liquid = 1.0030 cm³/g
We need to calculate the final pressure
Using formula for constant volume change
Put the value into the formula
Hence, The developed pressure is 205.75 bar.
