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2 years ago

Identify the type of the bond

Chemistry

1 answer:

julsineya [31]2 years ago

8 0

That is phosphorus trichloride and a COVALENT BOND

Cl needs one electron and P has metallic character, it donates electron easy

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True/False (A= True & B =False) 46. Blood is a tissue. 47. Elastic cartilage is found in the ears, nose, epiglottis and lary

swat32

Answer:

46.A 47.B 48.B 49.A.50.A.51.B.52.B

5 0

3 years ago

At one time in the Earth’s history, many people thought the world was flat. Which best explains why the model of the Earth is no

GenaCL600 [577]

Answer:

Models are limited by science - the more that was discovered, the better the model could be made.

Explanation:

Models in science are meant to represent things in science. Since science controls the reliability of a model, when science changes, so does the model. Otherwise the model would be pseudoscientific.

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3 years ago

A sample of argon gas has a volume of 795 mL at a pres-sure of 1.20 atm and a temperature of 116 ∘C. What is the final volume of

jek_recluse [69]

Answer: The volume when the pressure and temperature has changed is $1.6\times 10^2mL$

Explanation:

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

Let us assume:

$P_1=1.20atm\\V_1=795mL\\T_1=116^oC=[116+273]K=389K\\P_2=0.55atm\\V_2=?mL\\T_2=75^oC=[75+273]K=348K$

Putting values in above equation, we get:

$\frac{1.20atm\times 795mL}{389K}=\frac{0.55atm\times V_2}{348K}\\\\V_2=\frac{1.20\times 795\times 348}{0.55\times 389}=1.6\times 10^3mL$

Hence, the volume when the pressure and temperature has changed is $1.6\times 10^2mL$

5 0

3 years ago

Calculate the energy of an electron in the n = 2 level of a hydrogen atom.

ANEK [815]

Answer: The energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

Explanation:

Given: n = 2

The relation between energy and $n^{th}$ orbit of an atom is as follows.

$E = - \frac{13.6}{n^{2}} eV$

Substitute the values into above formula as follows.

$E = - \frac{13.6}{n^{2}} eV\\= - \frac{13.6}{(2)^{2}}\\= - 3.40 eV$

The negative sign indicates that energy is being released.

Thus, we can conclude that the energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

5 0

2 years ago

Use the normal boiling points: propane, C3H8, –42.1˚C; butane, C4H10, –0.5˚C; pentane, C5H12, 36.1˚C; hexane, C6H14, 68.7˚C; hep

svlad2 [7]

Answer:

The answer to your question is 126.1°C

Explanation:

Boiling point Difference of boiling points

C₃H₈ - 42.1°C

C₄H₁₀ - 0.5°C 41.6 °C

C₅H₁₂ 36.1°C 36.6°C 41.6 - 36.6 = 5°C

C₆H₁₄ 68.7°C 32.6°C 36.6 - 32.6 =4°C

C₇H₁₆ 98.4°C 29.7°C 32.6 - 29.7 = 2.9°C

We can observe on the table that the difference of boiling points diminishes 1°C when the hydrocarbon has one more carbon, then the difference of temperature between the hydrocarbon of 8 carbons and the hydrocarbon of 7 carbons must be 2°C.

So, this difference is 29.7°C - 2°C = 27.7°C.

And the boiling point of octane is approximately 98.4 + 27.7°C = 126.1°C

7 0

2 years ago

Identify the type of the bond​

Identify the type of the bond