Answer:
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Answer : The partial pressure of 
and 
are, 84 torr and 778 torr respectively.
Explanation : Given,
Mass of = 15.0 g
Mass of = 22.6 g
Molar mass of = 197.4 g/mole
Molar mass of = 32 g/mole
First we have to calculate the moles of and .
and,
Now we have to calculate the mole fraction of and .
and,
Now we have to partial pressure of and .
According to the Raoult's law,
where,
= partial pressure of gas
= total pressure of gas
= mole fraction of gas
and,
Therefore, the partial pressure of and are, 84 torr and 778 torr respectively.
Answer:
We can use heat = mcΔT to determine the amount of heat, but first we need to determine ΔT. Because the final temperature of the water is 55°C and the initial temperature is 20.0°C, ΔT is as follows:
ΔT = Tfinal − Tinitial = 55.0°C − 20.0°C = 35.0°C
given the specific heat of water as 1 cal/g·°C. Substitute the known values into heat = mcΔT and solve for amount of heat:
= heat=(75.0 g)(1 cal/ g· °C )(35.0°C) =
= 75x1x35=2625 cal
Hey there!:
Molar mass AgNO3 = 169.87 g/mol
Number of moles:
moles of solution = mass of solute / molar mass
moles of solution = 18.7 / 169.87
moles of solution = 0.110084 moles of AgNO3
Volume in liters:
250.0 mL / 1000 => 0.25 L
Therefore:
Molarity = moles of solution / Volume of solution ( L )
Molarity = 0.110084 / 0.25
=> 0.440 M
Hope that helps!
Answer:
they leads to water full of village
