Argon (Ar): [Ne]3s23p6 core electrons:__ valence electrons:__
2 answers:
Answer : Core electrons = 10
Valence electrons = 8
Explanation :
Core electrons : They are the electrons in an atom that do not participate in bonding.
Valence electrons : They are electrons in an atom that participate in bonding.
Electronic configuration : It is defined as the representation of electrons around the nucleus of an atom.
Number of electrons in an atom are determined by the electronic configuration.
The electronic configuration of argon (Ar) will be:
The electronic configuration of neon (Ne) will be:
So, the electronic configuration of argon (Ar) in noble gas notation will be:
In the given electronic configuration of argon, the electrons present in 1st shell and 2nd shell are the core electrons and the electrons present in 3rd shell are the valence electrons. That means,
Number of core electrons = 2 + 2 + 6 = 10
Number of valence electrons = 2 + 6 = 8
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Answer:
Hello your question is poorly written below is the well written question
Uranium, an important component of both nuclear weapons and nuclear reactors, has two major isotopes, U-238, which has a half-life of approximately 4.5 billion years, and U-235, which has a half-life of approximately 700 million years. Both were present in equal amounts at the time of the creation of the Earth, 4.5 billion years ago. How many years after the creation of the Earth had the amount of radiation from uranium decayed to half the amount present at the time of the creation of the Earth
Answer : 140 billion years
Explanation:
Given that :
U-238 h1/2 = 4.5 billion years
U-235 h1/2 = 700 million years
At the beginning both Isotopes where present in equal amount
Determine the T years before the amount of Uranium decays to Half
T = ? N'2 = N1 / 2
we know that N = No ( 1/2 )^h where h = time / half-life time
attached below is the detailed solution of the given problem
