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Maurinko [17]
3 years ago
12

Argon (Ar): [Ne]3s23p6 core electrons:__ valence electrons:__

Chemistry
2 answers:
Artyom0805 [142]3 years ago
6 0

Answer : Core electrons = 10

Valence electrons = 8

Explanation :

Core electrons : They are the electrons in an atom that do not participate in bonding.

Valence electrons : They are electrons in an atom that participate in bonding.

Electronic configuration : It is defined as the representation of electrons around the nucleus of an atom.  

Number of electrons in an atom are determined by the electronic configuration.

The electronic configuration of argon (Ar) will be:

1s^22s^22p^63s^23p^6

The electronic configuration of neon (Ne) will be:

1s^22s^22p^6

So, the electronic configuration of argon (Ar) in noble gas notation will be:

[Ne]3s^23p^6

In the given electronic configuration of argon, the electrons present in 1st shell and 2nd shell are the core electrons and the electrons present in 3rd shell are the valence electrons. That means,

Number of core electrons = 2 + 2 + 6 = 10

Number of valence electrons = 2 + 6 = 8

irga5000 [103]3 years ago
3 0

10 core elections

8 valence elections

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C – 19,9%, H – 2,2%, N – 11,6%, O – x%

M=120\frac{g}{mol}

1 percentage

The entire molecule is 100% and all the components of the compound add up to 100%.

100% - 19,9% - 2,5% - 11,6% = 66,1%

The compound contains 66,1% oxygen.

2 molar masses

M_{C}=12,01\frac{g}{mol}

M_{H}=1,008\frac{g}{mol}

M_{O}=15,999\frac{g}{mol}

M_{N}=14,007\frac{g}{mol}

3 masses

The compound has a molar mass of 120g/mol. So one molecule weighs 120 g. To find out how much the percentage of a component weighs, you have to calculate it using the molar mass.

<u>carbon</u>

19,8% of 120g

m=120g*0,198\\m=23,76g

One molecule contains 23,76g of carbon.

<u>hydrogen</u>

2,5% of 120g

m=120g*0,025\\m=3g

One molecule contains 3g of hydrogen.

<u>oxygen</u>

66,1% of 120g

m=120g*0,661\\m=79,32g

One molecule contains 79,32g of oxygen.

<u>nitrogen</u>

11,6% of 120g

m=120g*0,0,116\\m=13,92g

One molecule contains 13,92g of nitrogen.

4 amount of substance

<u>carbon</u>

<u />n=\frac{23,76g}{12,01\frac{g}{mol} }\\n=1,98mol<u />

The compound contains about 2 moles of carbon.

<u>hydrogen</u>

n=\frac{3g}{1\frac{g}{mol} }\\n=3mol

The compound contains about 3 moles of hydrogen.

<u>oxygen</u>

n=\frac{79,32g}{15,999\frac{g}{mol} }\\n=4,96mol

The compound contains about 5 moles of oxygen.

<u>nitrogen</u>

<u />n=\frac{13,92g}{14,007\frac{g}{mol} }\\n=0,99mol<u />

The compound contains about 1 moles of nitrogen.

5. molecular formula

The formula results from the ratio of the amounts of substance.

n_{C} :n_{H} :n_{O} :n_{N} =2:3:5:1\\C_{2}H_{3}NO_{5}

8 0
2 years ago
What is the concentration of a solution in which 10.0 g of AgNO3 is dissolved in 500 mL of solution?
Zigmanuir [339]

molar concentration of AgNO₃ solution = 0.118 mole/L

Explanation:

Because we have the volume of the solution and there is no information about the density of the solution I will asume that you ask for the molar concentration.

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number of moles of AgNO₃ = 10 / 170 = 0.0588

molar concentration = number of moles / volume (L)

molar concentration of AgNO₃ solution = 0.0588 / 0.5

molar concentration of AgNO₃ solution = 0.118 mole/L

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brainly.com/question/1286583

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Answer:

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Explanation:

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