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Sindrei [870]
3 years ago
13

Using monochromatic light of 410 nm wavelength, a single thin slit forms a diffraction pattern, with the first minimum at an ang

le of 40.0° from central maximum. The same slit, when illuminated by a new monochromatic light source, produces a diffraction pattern with the second minimum at a 60.0° angle from the central maximum. What is the wavelength of this new light?a. 256 nm b. 283 nm c. 307 nm d. 329 nm e. none of these
Physics
1 answer:
VLD [36.1K]3 years ago
5 0

Answer:

c. 307 nm

Explanation:

angular position of first dark fringe =  λ / d ,   λ is wavelength and  d is width of slit .

(40 x π ) / 180 = 410 / d

angular position of second  dark fringe =  2 x λ / d ,   λ is wavelength and  d is width of slit .

(60 x π ) / 180 = 2 x λ / d

Dividing these equations

60 / 40 =  2 x λ / 410

λ = 307.5 nm.

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It makes it lighter when its closer and heavier when its farther way.

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Paola can flex her legs from a bent position through a distance of 20.1 cm. Paola leaves the ground when her legs are straight,
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The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/s^{2}.

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To determine Paola's acceleration, the third equation of free fall is appropriate.

i.e V^{2} = U^{2} ± 2as

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From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.

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Visit: brainly.com/question/17493533

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