a heater 60w evaporates 6×10–3kg of boiling water in 60s.what is the specific latent heat of vaporisation of water in jkg–1
1 answer:
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The energy of a single photon is given by:
where
E is the energy
h is the Planck constant
f is the frequency of the light
The light in our problem has a frequency
, so the energy of each photon of that light is:
where
E is the energy
h is the Planck constant
f is the frequency of the light
The light in our problem has a frequency
Answer:
a. 139.748J
b.3.486m/s
c.zero
Explanation:
a. Given the mass of the child as 23.0kg, rope length is 2.1mand incline is 45°
Potential energy during release is calculated as:
#Find vertical difference of when the swing is at rest (2.1m) and when the child is pulled back.
Find the height when the child is pulled back:
#therefore,vertical difference is 2.1m-1.48m=0.62m
#Hence the potential energy during release is 139.748J
b. From a, above, we have PE=139.748J, M=23.0kg.
At the bottom, all the PE will be transferred into KE. Potential energy is calculated as:
#Hence the velocity at the bottom of the swing is 3.486m/s
c. Work is calculated as the product of force by distance.
From a, b above we have mass as 23.0kg .
-since the distance of the ropes remained constant the change in distance is zero:
Therefore the work in the ropes is 0,zero.