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Blababa [14]
2 years ago
13

a heater 60w evaporates 6×10–3kg of boiling water in 60s.what is the specific latent heat of vaporisation of water in jkg–1​

Physics
1 answer:
geniusboy [140]2 years ago
4 0

Your question doesn't look right, so lemme assume you meant this.

A heater marked 60w evaporate 6x 10^-³kg of boiling water in 60 seconds. What is the specific latent heat of vaporization of water in jkg?

so you can understand it better..

Latent heat of evaporation is the heat required required to change water to vapor at the same temperature.(100°C)

eg. water boils at 100°C and in presence of more heat it turns to vapor at that Same temperature.

This heat is know as latent heat of Vaporization.

it's give by H=mL

where L is the specific latent heat of vaporization.

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The centripetal force exerted on stunt motorcyclist Biker Bob while riding on the inner vertical surface of a circular track is:
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option C

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3 years ago
A bowling ball of mass 5.8 kg moves in a
evablogger [386]

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Velocity of the ping pong ball must be = V2= 6,035.34m/s

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m2= mass of the ping pong ball= 1.528 g/1000=  0.001528kg

v2= velocity of the ping pong ball

Momentum of the bowling ball= M1= m1v1= 5.8* 1.59= 9.222 kg-m/s

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