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zepelin [54]
3 years ago
12

You are travelling at 60.0 mph on the Grand Central Parkway near exit 10 where it is (nearly) parallel to the Long Island Expres

sway (LIE). a) A truck on the LIE going in the SAME direction as you is travelling at 55.0 mph. What is YOUR relative velocity compared to that truck? b) A truck on the LIE going in the OPPOSITE direction as you is travelling at 55.0 mph. What is YOUR relative velocity compared to that truck?
Physics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0

Answer:

a)Vr= 5 mph

b)Vr= 115 mph

Explanation:

Lets

your velocity ,u= 60 mph

velocity of truck ,v= 55 mph

When object are moving in opposite direction the relative velocity  = u +v When object are moving in opposite direction the relative velocity  = u - v

a)

Truck is moving in the same direction ,so the  relative velocity

Vr= = u - v

Vr= 60 - 55

Vr= 5 mph

b)

Truck is moving in the opposite direction ,so the  relative velocity

Vr= = u+v

Vr= 60 + 55

Vr= 115 mph

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Answer:

you can build a mote around your castle and put crocodiles in it.

Explanation:

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4 0
2 years ago
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Compute your average velocity in the following two cases: (a) You walk 50.2 m at a speed of 2.21 m/s and then run 50.2 m at a sp
Readme [11.4K]

Answer:

a) 2.87 m/s

b) 3.23 m/s

Explanation:

The avergare velocity can be found dividing the length traveled d by the total time t.

a)

For the first part we easily know the total traveled length which is:

d = 50.2 m + 50.2 m = 100.4 m

The time can be found dividing the distance by the velocity:

t1 = 50.2 m / 2.21 m/s = 22.7149 s

t2 = 50.2 m / 4.11 m/s = 12.2141 s

t = t1 +t2 = 34.9290 s

Therefore, the average velocity is:

v = d/t =2.87 m/s

b)

Here we can easily know the total time:

t = 1 min + 1.16 min = 129.6 s

Now the distance wil be found multiplying each velocity by the time it has travelled:

d1 = 2.21 m/s * 60 s = 132.6 m

d2 = 4.11 m/s *(1.16 * 60 s) = 286.056 m

d = 418.656 m

Therefore, the average velocity is:

v = d/t =3.23 m/s

5 0
3 years ago
The quartz crystal used in an electric watch vibrates with a frequency of 32,768 Hz. What is the period of the crystal's motion?
Elan Coil [88]

Answer:

Time period, T=3.05\times 10^{-5}\ s

Explanation:

Given that,

The quartz crystal used in an electric watch vibrates with a frequency of 32,768 Hz, f = 32768 Hz

We need to find the period of the crystal's motion. The relationship between the frequency and the time period is given by :

T=\dfrac{1}{f}

T is the time period of the crystal's motion.

Time period is given by :

T=\dfrac{1}{32768}

T=3.05\times 10^{-5}\ s

So, the time period of the crystal's motion is 3.05\times 10^{-5}\ s. Hence, this is the required solution.

8 0
3 years ago
SOMEONE HELP PLEASE ASAP I BELIEVE THE ANSWER IS C OR D
Serhud [2]
You are correct the answer would be C

hope i helps
4 0
4 years ago
Simple Pendulum: A 34-kg child on an 18-kg swing set swings back and forth through small angles. If the length of the very light
SIZIF [17.4K]

Answer:

The correct answer is "4.443 sec".

Explanation:

Given:

Mass of child,

= 34 kg

Mass of swing,

= 18 kg

Length,

= 4.9 m

The time period of pendulum will be:

T = 2 \pi \sqrt{4g}

  = 2 \pi \sqrt{\frac{4.9}{9.8} }

  = 4.443 \ sec  

5 0
3 years ago
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