Answer:
728 N
Explanation:
= length of the wire = 0.680 m
= mass of the steel wire = 0.0046 kg
= Fundamental frequency = 261.6 Hz
= tension force in the steel wire
Fundamental frequency in wire is given as
<h2>The frequency of driver is 700 Hz</h2>
Explanation:
The frequency of wave in a string is given by the relation
n = 
here n is the frequency
p is the number of antinodes and l is the length of string .
T is the tension in string and m is the mass per unit length
Thus 420 =
I
Now if there is 5 antinodes , the value of p = 5
Thus n = 
II
Dividing II by I , we have
n/420 = 5/3
or n = 5/3 x 420 = 700 Hz
Answer:
b) there must be a component of force parallel to the motion of the object.
Explanation:
We know that work done on a body by an external force is calculated by the formula given below:
W = F.d = Fd Cos θ
where,
W = Work Done by the force on the body
F = Magnitude of force
d = displacement of the body
θ = The angle between the direction of motion of the body and the force applied
It is clear from the formula of the work done, that "F Cosθ" represents the component of the force, that is acting in the direction of motion of the object or parallel to the direction of motion of the object. So, if there is no component of force parallel to motion of object, then this factor will become zero. As a result, the work done will also be zero.
Therefore, the correct option will be:
b) <u>there must be a component of force parallel to the motion of object.</u>
