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Bad White [126]
3 years ago
15

If you know the power rating of an appliance and the voltage of the line it is attracted to , you can calculate the current the

appliance uses by
Physics
2 answers:
marshall27 [118]3 years ago
8 0

                                Power = (voltage) times (current)

Divide each side
by voltage:              Power / voltage  =  current .

If you know the power and the voltage, then you can divide
the power by the voltage, and the quotient is the current.
rusak2 [61]3 years ago
3 0

Dividing The Power by the voltage im pretty sure.

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. A truck is traveling at a speed of 25.0 m/sec along a level road. A crate is resting on the bed of the truck, and the coeffici
OLga [1]

Answer:

98.12 m

Explanation:

Initial speed(v) = 25.0 m/s

Coefficient of static friction (u) = 0.650

The minimum value of the coefficient of kinetic friction should be the coefficient of static friction.

Kinetic friction is given as

umg = ma (a is the required acceleration)

We then have

a = -ug

= -(0.65*9.8)

= -6.37 m/s^2

The shortest distance d is obtained by

d = (V^2 - v^2)/ 2a

V = 0 m/s (final velocity)

d = (0 - 25^2) / 2(-6.37)

d = -625/-6.37

d = 98.12 m

5 0
3 years ago
If you exert a force of 700 N to walk 6m up a flight of stairs in 6s how much power do you lose?
SashulF [63]

Answer:

700 watts

Explanation:

From the question, it is given that;

Force = 700N

Distance = 6m

Time = 6s

<u>First step:</u> we derive the formula that relates Power, distance and time, from first principle

Power = \frac{Energy}{Time}

But Energy is Force X Distance

Power = \frac{Force X Distance}{Time}

Power = \frac{(700) X (6)}{6}

Power = 700 watts

The power you will lose after walking the stairs is 700 watts

6 0
3 years ago
What can subatomic particles be broken down into?
AfilCa [17]
Subatomic particles cannot be broken down any further
5 0
3 years ago
A small motor uses 200 watts to do 4000 joules of work. How much time this take to occur?​
Firdavs [7]
The answer is 20 seconds.
6 0
3 years ago
Find the work done in pumping gasoline that weighs 6600 newtons per cubic meter. A cylindrical gasoline tank 3 meters in diamete
almond37 [142]

Answer:

<em>work done in pumping the entire fuel is 1399761 J</em>

Explanation:

weight per volume of the gasoline = 6600 N/m^3

diameter of the tank = 3 m

length of the tank = 6 m

The height of the tractor tank above the top of the tank = 5 m

The total volume of the fuel is gotten below

we know that the tank is cylindrical.

<em>we assume that the fuel completely fills the tank.</em>

therefore, the volume of a cylinder =  

where r = radius = diameter ÷ 2 = 3/2 = 1.5 m

volume of the cylinder = 3.142 x  x 6 = 42.417 m^3

we then proceed to find the total weight of the fuel in Newton

total weight = (weight per volume) x volume

total weight = 6600 x 42.417 = 279952.2 N

therefore,

the work done to pump the fuel through to the 5 m height = (total weight of the fuel) x (height through which the fuel is pumped)

work done in pumping = 279952.2 x 5 = <em>1399761 J</em>

5 0
3 years ago
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