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Bad White [126]
3 years ago
15

If you know the power rating of an appliance and the voltage of the line it is attracted to , you can calculate the current the

appliance uses by
Physics
2 answers:
marshall27 [118]3 years ago
8 0

                                Power = (voltage) times (current)

Divide each side
by voltage:              Power / voltage  =  current .

If you know the power and the voltage, then you can divide
the power by the voltage, and the quotient is the current.
rusak2 [61]3 years ago
3 0

Dividing The Power by the voltage im pretty sure.

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Please answer as soon as possible. <br><br> A Physics question about electricity and circuits.
kifflom [539]
R=144 ohms with method shown on photo

6 0
3 years ago
Moving force of air flows through areas of high pressure to areas of low pressure
vazorg [7]

The answer is true i hope this helps

7 0
3 years ago
Read 2 more answers
26. The equation E=hf describes the energy of each photon in a beam of light. If Planck’s constant, h, were larger, would photon
Elenna [48]
The equation of the energy of a photon is E=h*f.

If we increase the Planck's constant h, the energy would increase. 

For example, lets double the value of Planck's constant and name it H:

H=2*h. Now lets put that into the equation for energy that we will call E₂:

E₂=H*f=2*h*f=2*E. 

So we can clearly see that E₂=2*E or that if we double Planck's constant, the energy also doubles. 
6 0
3 years ago
For elevator questions, does the weight of a person increase when the elevator is going up or if it's going down-
TiliK225 [7]

The weight of a person increase when the elevator is going up.

<h3>Weight of the person in the elevator</h3>

The weight of the person in the elevator is calculated as follows;

<h3>When the person is going up</h3>

F = ma + mg

F = m(a + g)

where;

  • a is acceleration of the person
  • g is acceleration due to gravity

<h3>When the person is going down</h3>

F = mg - ma

F = m(g - a)

Thus, the weight of a person increase when the elevator is going up.

Learn more about weight here: brainly.com/question/2337612

#SPJ1

6 0
2 years ago
A solid 0.4550 kg ball rolls without slipping down a track toward a vertical loop of radius R = 0.6750 m . What minimum translat
Talja [164]

Answer:

u = 3.35 m/s

Explanation:

given,

mass , m = 0.455 kg  

R = 0.675 m

Height of Loop = 1.021 m

the speed required at the top of loop be v

equating the force vertically

m g =\dfrac{mv^2}{r}

9.81 =\dfrac{v^2}{0.675}

v² = 6.622

v = 2.57 m/s

Let the initial speed of ball be u

using conservation of energy

\dfrac{1}{2}mu^2 + \dfrac{1}{2}I\omega^2 + m g h = \dfrac{1}{2}I\omega^2 + \dfrac{1}{2}mv^2+ m g (2 R)

where, I =\dfrac{2}{5}mr^2

\dfrac{1}{2}mu^2 + \dfrac{1}{2}(\dfrac{2}{5}mr^2)(\dfrac{u}{r})^2 + m g h = \dfrac{1}{2}(\dfrac{2}{5}mr^2)(\dfrac{v}{r})^2 + \dfrac{1}{2}mv^2+ m g (2 R)

0.7 u^2 + g H = 0.7 v^2 + g(2R)

0.7 u^2 +9.81 \times 1.021= 0.7\times 2.57^2 + 9.81 \times 2\times 0.675)

0.7 u² = 7.85092

u² = 11.2156

u = 3.35 m/s

the initial  speed is 3.35 m/s

8 0
3 years ago
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