Answer:
Explanation:
For critical angle C the relation is
SinC = 1 / μ where μ is refractive index of denser medium with respect to rarer medium .
In case of A , refractive index of denser medium with respect to rarer medium .is equal to 1.33 / 1 = 1.33
In case of B , refractive index of denser medium with respect to rarer medium .is equal to 2.42 / 1 = 2.42
In case of C , refractive index of denser medium with respect to rarer medium .is equal to 2.42 / 1.33 = 1.82
In case of D , refractive index of denser medium with respect to rarer medium .is equal to 1.50 / 1.33 = 1.127
In case of D , refractive index is lowest , critical angle will be highest .
In case of B , refractive index of denser medium with respect to rarer medium .is highest so critical angle will be lowest.
Ranking from largest to smallest
D > A >C >B .
Because of BOMDAS, you do the multiplication first.
(3.0x10) - 4 - (1.7x10) - 6
= 30 - 4 - 17 - 6
= 3
<span>Displacement of the oscillator can be expressed in the mathematical form as:
x(t) = A*cos (ωt + δ),
therefore acceleration would be represented as => a = ¨x = â’ω^2*A*cos (ωt + δ),
the maximum acceleration will happen when the cosine is -1.
Hence, maximum acceleration => a-max = A*ω^2
The force associated with acceleration is F = ma.
Therefore maximum amplitude is
A = F / (m*ω^2)
= F / (4Ď€^2 * m * f^2) where f is the frequency of oscillation.
putting values in above equation we ge:
A = 50000 / 4Ď€^2 * 10^â’4 Ă— (10^6)^2
= 1.25 * 10^â’5
hence 1.25 * 10^-5 m/s^2</span>
Answer:
True
Explanation: In pulley's , length of cables doesn't change.
Answer:
The normal force is the force that surfaces exert to prevent solid objects from passing through each other. If the object is at rest, the net force on the object is equal to zero. Therefore, the downward force (weight) must be equal to the upward force (normal force).