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ki77a [65]
3 years ago
14

In the Milky Way Galaxy, where would you expect to find the bulge?

Physics
1 answer:
nalin [4]3 years ago
3 0

Answer:

at the sun???

Explanation:

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The lower atmosphere is mostly warmed by radiated heat from Earth's surface. However, water heats up and cools down more slowly
JulsSmile [24]
The answer is B. On a sunny day, the air over a lake will be cooler than the air over the bordering land.
6 0
3 years ago
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You are called to the crime scene immediately and you begin your investigation at 2 PM. The first thing you do is take the tempe
adell [148]

As per Newton's law of cooling we know that

\frac{\Delta T}{dt} = k(T_avg - T_s)

in 5 hours the body temperature becomes 79.6 from 84.4

while the surrounding temperature is given as 68 degree F

now from above formula

\frac{84.4 - 79.6}{5} = k (\frac{84.4 + 79.6}{2} - 68)

0.96 = k(14)

now let say the person died "t" time ago

now we will have

\frac{98.6 - 84.4}{t} = k (\frac{98.6 + 84.4}{2} - 68)

\frac{14.2}{t} = k(23.5)

\frac{14.2}{t} = \frac{0.96}{14}(23.5)

t = 8.8 hours = 9hours (approx)

so he died at approx 5 Am in  morning

5 0
3 years ago
Why does changing the shape of an object have no effect on the density?
iren [92.7K]
Because the object is still made of the same material 
Density is not affected by the weight and shape of an object its affected by how concentrated the atoms are in a given volume 
7 0
3 years ago
A ball is thrown downward from the top of a building with an initial speed of 25 m/s.
Bumek [7]

Answer:

h = 69.6 m

Explanation:

Data:

  • Vo = 25 m/s
  • t = 2.0 s
  • g = 9.8 m/s²
  • h = ?

Formula:

  • \boxed{\bold{h=V_{0}*t+\frac{g*(t)^{2}}{2}}}

Replace and solve:

  • \boxed{\bold{h=25\frac{m}{s}*2.0\ s+\frac{9.8\frac{m}{s^{2}}*(2.0\ s)^{2}}{2}}}
  • \boxed{\bold{h=50\frac{m}{s^{2}}+\frac{9.8\frac{m}{s^{2}}*4\ s^{2}}{2}}}
  • \boxed{\bold{h=50\ m+\frac{39.2\ m}{2}}}
  • \boxed{\bold{h=50\ m+19.6\ m}}
  • \boxed{\boxed{\bold{h=69.6\ m}}}

The building has a height of <u>69.6 meters.</u>

Greetings.

5 0
3 years ago
How much power does it take to lift 30.0 N 10.0 m high in 5.00 s?
Rudik [331]

Power = work/time = (Force times distance)/time

= (30N *10.0m)/5.00s = 300/5 = 60 Watts

7 0
3 years ago
Read 2 more answers
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