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Fantom [35]
3 years ago
10

What kinds of telescopes are used to measure parallax

Physics
1 answer:
Elina [12.6K]3 years ago
3 0
Hipparcos is used to measure parallax
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Three balls of equal mass are fired simultaneously with equal speeds from the same height h above the ground. Ball 1 is fired st
pantera1 [17]

Answer:

d) v1 = v2 = v3

Explanation:

This can be answered using conservation of energy. We calculate the mechanical energy E=K+U (sum of kinetic and gravitational potential energies) at the original and final points, and impose they are equal.

At the original point we have, for the three balls:

E_i=K_i+U_i=\frac{mv_i^2}{2}+mgh_i=\frac{mv^2}{2}+mgh

At the final point we have, for the three balls:

E_f=K_f+U_f=\frac{mv_f^2}{2}+mgh_f=\frac{mv_f^2}{2}

Since we have E_i=E_f, and E_i is the same for all balls, then E_f is the same for all balls, which means that v_f, the final velocity, is the same for all balls.

4 0
3 years ago
A positron is an elementary particle identical to an electron except that its charge is . An electron and a positron can rotate
denis23 [38]

Explanation:

According to the energy conservation,

          F_{centripetal} = F_{electric}

            \frac{mv^{2}}{r} = \frac{kq^{2}}{d^{2}}

           v^{2} = \frac{kq^{2}r}{d^{2}m}

                 = \frac{9 \times 10^{9} N.m^{2}/C^{2} \times 1.6 \times 10^{-19} C \times 0.75 \times 10^{-9} m}{(1.50 \times 10^{-9}m)^{2} \times 9.11 \times 10^{-31} kg}

                = 8.430 \times 10^{10} m^{2}/s^{2}

             v = \sqrt{8.430 \times 10^{10} m^{2}/s^{2}}

                = 2.903 \times 10^{5} m/s

Formula for distance from the orbit is as follows.

               S = 2 \pi r

                  = 2 \times 3.14 \times 0.75 \times 10^{-9} m

                  = 4.71 \times 10^{-9} m

Now, relation between time and distance is as follows.

                T = \frac{S}{v}

       \frac{1}{f} = \frac{S}{v}

or,           f = \frac{v}{S}          

                = \frac{2.903 \times 10^{5} m/s}{4.71 \times 10^{-9} m}      

                = 6.164 \times 10^{13} Hz

Thus, we can conclude that the orbital frequency for an electron and a positron that is 1.50 apart is 6.164 \times 10^{13} Hz.

7 0
3 years ago
Which of the following actions is an example of an improvement in human capital?
kap26 [50]

Answer: D

Explanation:

Frank’s Furniture trains all of its employees to use computers is an example of an improvement in human capital.

8 0
3 years ago
Inside a television picture tube there is a build-up of electrons (charge of 1. 602 × 10–19 C) with an average spacing of 38. 0
Olin [163]

The magnitude of the electric field inside the picture tube is 998.476 kN/C.

<h3>What is an electric field?</h3>

It is an area in the space where a charged particle experiences a force. It can be calculated by the formula,

E =\dfrac {kQ}{r^2 }

Where,

E = electric field produced

Q = charge =  1.602 \times  10^{-19}\rm \  C

r = distance = 38 \times  10^{-9}\rm \  m

k = Coulomb's constant = 9 \times 10^9 \rm \ N. m2 / C2

Put the values in the formula,

E = \dfrac {9 \times 10^9\times 1.602 \times  10^{-19}}{(38 \times  10^{-9})^2}\\\\E = 998.476 \rm \ kN/C

Therefore, the magnitude of the electric field inside the picture tube is 998.476 kN/C.

Learn more about the electric field:

brainly.com/question/3783640

8 0
2 years ago
Summarize the two stages of cellular respiration.
denpristay [2]
<span>Glycolysis. In glycolysis, glucose—a six-carbon sugar—undergoes a series of chemical transformations. In the end, it gets converted into two molecules of pyruvate, a three-carbon organic molecule. 
Pyruvate oxidation.
Each pyruvate from glycolysis goes into the mitochondrial matrix—the innermost compartment of mitochondria. </span>
5 0
3 years ago
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