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Y_Kistochka [10]
3 years ago
13

4: Which of the following is true of an object in a circular motion at a constant speed?

Physics
1 answer:
Andre45 [30]3 years ago
7 0
Yes it could. And IT IS !
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The third floor of a house is 8m above street level. How much work is needed to move a 136kg refrigerator to the third floor?
jonny [76]

m = Mass of the refrigerator to be moved to third floor = 136 kg

g = Acceleration due to gravity by earth on the refrigerator being moved = 9.8 m/s²

h = Height to which the refrigerator is moved  = 8 m

W = Work done in lifting the object

Work done in lifting the object is same as the gravitational potential energy gained by the refrigerator. hence

Work done = Gravitation potential energy of refrigerator

W = m g h

inserting the values

W = (136) (9.8) (8)

W = 10662.4 J



8 0
2 years ago
Calculate the orbital speed (in m/s) of a satellite that circles the Earth with a time period of 12.00 hours. The mass of the Ea
Hoochie [10]

Answer:

v = 3869 m/s

Explanation:

As we know that the orbital speed of the satellite is given as

v = \sqrt{\frac{GM}{r}}

also we know that

time period of the revolution is given as

T = \frac{2\pi r}{v}

now from above equation we know that

T = \frac{2\pi (\frac{GM}{v^2})}{v}

T = \frac{2\pi GM}{v^3}

so we will have

v = (\frac{2\pi GM}{T})^{1/3}

now plug in all data in this equation

v = (\frac{2\pi (6.67 \times 10^{-11})(5.97 \times 10^{24})}{12 \times 3600})^{1/3}

v = 3869 m/s

3 0
2 years ago
If p(a)=0.07692, p(b)=0.25, and probability of a and b. =0.01923, what is probability of a or b. to four decimal places? select
Triss [41]

Answer:

p(a) * p(b) = .01923

p(b) = .01923 / .07692 = .2500

5 0
1 year ago
More Density Graphi Questions
nata0808 [166]

Answer:

?

Explanation:

6 0
3 years ago
A thin rod of length 0.79 m and mass 130 g is suspended freely from one end. It is pulled to one side and then allowed to swing
-Dominant- [34]

Answer:

a) 0.3965 j

b) 0.3112 m

Explanation:

The picture attached explains it all. Thank you

3 0
3 years ago
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