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vladimir1956 [14]
3 years ago
9

Which is one way that scientist communicate the results of an experiment

Chemistry
2 answers:
olganol [36]3 years ago
4 0

Answer:

The way in which the scientist communicates the results of an experiment is through the publication of the scientific article in a scientific journal.

Explanation:

The way in which the scientist communicates the results of an experiment is through the publication of the scientific article in a scientific journal.

The publication of a scientific or technical article is a way of transmitting to the technical-scientific community the knowledge of new discoveries, and the development of new materials, techniques and methods of analysis in the various areas of science.

 Many educational and / or research institutions, and several commercial companies often require their professionals to present the progress of their work and / or study through the publication of technical and scientific articles. In addition, institutions or companies that publish constantly enjoy the technical recognition of their name, which helps to attract greater investments and gains for this organization.

Slav-nsk [51]3 years ago
3 0
Draw conclusions,............
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A 50.0 mL solution of 0.141 M KOH is titrated with 0.282 M HCl . Calculate the pH of the solution after the addition of each of
Kobotan [32]

Answer:

pH =1 2.84

Explanation:

First we have to start with the <u>reaction</u> between HCl and KOH:

HCl~+~KOH->~H_2O~+~KCl

Now <u>for example, we can use a volume of 10 mL of HCl</u>. So, we can calculate the moles using the <u>molarity equation</u>:

M=\frac{mol}{L}

We know that 10mL=0.01L and we have the concentration of the HCl 0.282M, when we plug the values into the equation we got:

0.282M=\frac{mol}{0.01L}

mol=0.282*0.01

mol=0.00282

We can do the same for the KOH values (50mL=0.05L and 0.141M).

0.141M=\frac{mol}{0.05L}

mol=0.141*0.05

mol=0.00705

So, we have so far <u>0.00282 mol of HCl</u> and <u>0.00705 mol of KOH</u>. If we check the reaction we have a <u>molar ratio 1:1</u>, therefore if we have 0.00282 mol of HCl we will need 0.00282 mol of KOH, so we will have an <u>excess of KOH</u>. This excess can be calculated if we <u>substract</u> the amount of moles:

0.00705-0.00282=0.00423mol~of~KOH

Now, if we want to calculate the pH value we will need a <u>concentration</u>, in this case KOH is in excess, so we have to calculate the <u>concentration of KOH</u>. For this, we already have the moles of KOH that remains left, now we need the <u>total volume</u>:

Total~volume=50mL+10mL=60mL

60mL=0.06L

Now we can calculate the concentration:

M=\frac{0.00423mol}{0.06L}

M=0.0705

Now, we can <u>calculate the pOH</u> (to calculate the pH), so:

pOH=-Log(0.0705)

pOH=1.15

Now we can <u>calculate the pH value</u>:

14=~pH~+~pOH

pH=14-1.15=12.84

8 0
3 years ago
Is it true or false that Science is a collection of facts that does not evolve. We have gained all the knowledge we can from sci
Masja [62]
false

because science is an ever-growing subject we can never stop learning from it and expanding our knowledge.

(sorry that's the best that I can do)
7 0
3 years ago
5. A particular anticodon is 5'-AGC-3'. The codon that is a precise complementary base pair match for this is 5'-AGU-3'. However
Veseljchak [2.6K]

Explanation:

Wobble Hypothesis given by Francis Harry Compton Crick states that 3rd base of mRNA codon can base pair with 1st base of a tRNA anticodon undergoing non-Watson-Crick.

The first 2 bases of the mRNA codon form Hydrogen bonds with the corresponding bases on tRNA anticodon in Watson-Crick manner. Through this, they only form the base pairs with the complimentary bases. However, formation of the Hydrogen bonds between 3rd base on codon and 1st base on anticodon can occur potentially in non-Watson-Crick manner.  

<u>Thus, the Wobble Hypothesis explains that why the multiple codons can code for single amino acid.</u>

3 0
3 years ago
Is there more or less air near sea level
vampirchik [111]

there is more air near sea level

7 0
2 years ago
What is the reduction half equation of Fe(s)+ 2 HC2H3O2(aq) → Fe(C2H3O2)2(aq) + H2(g)
Sonbull [250]

Answer:

2 H⁺ + 2e = H₂    ( reduction )

Explanation:

Fe( s ) + 2 CH₃COOH = Fe ( OOCCH₃ ) ₂ + H₂

Fe( s ) = Fe⁺² + 2e     ( oxidation )

2 H⁺ + 2e = H₂    ( reduction )

4 0
3 years ago
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