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Basile [38]
3 years ago
14

A company is testing drinking water and wants to ensure that ca content is below 155 ppm. What is the maximum amount of Ca that

would be allowed in a 890 g of water.
Chemistry
1 answer:
BabaBlast [244]3 years ago
7 0

Answer:

138 mg

Explanation:

A company is testing drinking water and wants to ensure that Ca content is below 155 ppm (= 155 mg/kg), that is, <em>155 milligrams of calcium per kilogram of drinking water</em>. We need to find the maximum amount of calcium in 890 g of drinking water.

Step 1: Convert the mass of drinking water to kilograms.

We will use the relation 1 kg = 1000 g.

890g \times \frac{1kg}{1000g} =0.890kg

Step 2: Calculate the maximum amount of calcium in 0.890 kg of drinking water

0.890gH_2O \times \frac{155mgCa}{1kgH_2O} = 138mgCa

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