Question

A company is testing drinking water and wants to ensure that ca content is below 155 ppm. What is the maximum amount of Ca that would be allowed in a 890 g of water.

Answer 1

Answer:

138 mg

Explanation:

A company is testing drinking water and wants to ensure that Ca content is below 155 ppm (= 155 mg/kg), that is, 155 milligrams of calcium per kilogram of drinking water. We need to find the maximum amount of calcium in 890 g of drinking water.

Step 1: Convert the mass of drinking water to kilograms.

We will use the relation 1 kg = 1000 g.

$890g \times \frac{1kg}{1000g} =0.890kg$

Step 2: Calculate the maximum amount of calcium in 0.890 kg of drinking water

$0.890gH_2O \times \frac{155mgCa}{1kgH_2O} = 138mgCa$