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Orlov [11]
3 years ago
13

Pls help i’m so confused

Physics
1 answer:
Shtirlitz [24]3 years ago
3 0
Okay! Let’s list what we know and what we want to know.

Initial velocity: 0 (since the truck is starting from rest)
Final velocity: ? (what we want to know)
Acceleration: 4.07
Distance: 6.31

Since we want to find the final velocity and the information gave us the distance travelled and the acceleration of the vehicle, we’re going to want to use this equation of motion:

Final Velocity^2 = Initial Velocity^2 + 2 * Acceleration * Distance

Let’s substitute what we know and work out the answer! Since the initial velocity of the truck is zero, it cancels out, so I’m going to take it out of the equation within the next couple of steps, leaving only (2 * acceleration * distance)

Final Velocity^2 = 0^2 + 2 * 4.07 * 6.31
Final Velocity^2 = 2 * 4.07 * 6.31
Final Velocity^2 = 51.3634

This gave us final velocity squared, in order to get the final velocity of the truck, we must square root the answer. Therefore:

Final Velocity = 7.167m/s^2

:)
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erma4kov [3.2K]

Answer:

The height is  h = 0.5224 \ m

Explanation:

From the question we are told that

   The combined mass of the child and the sled is  m =  58.0 \  kg

    The  speed of the sled is  u = 3.20 \ m/s

Generally applying SOHCAHTOA on the slope which the combined mass is down from

   Here the length of the slope(L)  where the combined mass slides through  is the hypotenuses

   while the height(h) of the height of the slope is the opposite

Hence from SOHCAHTOA

      sin (\theta) =  \frac{h}{L}

=>   Lsin(\theta) = h

Generally from the kinematic equation we have that

   v^2  = u^2 + 2aL

Here the u  is the initial velocity of the combined mass which is zero since it started from rest

 and  a is the acceleration of the combined mass which is mathematically evaluated as

       a =  g * sin (\theta )

      v^2  = u^2 + 2 *  g * sin (\theta )L

=>   2Lsin(\theta ) =  \frac{v^2 - u^2 }{g}

=>   h = \frac{ v^2 - u^2}{2g}

=>   h = \frac{ 3.20^2 - 0^2}{2 * 9.8 }

=>   h = 0.5224 \ m

6 0
3 years ago
Audible wavelengths. the range of audible frequencies is from about 20.0 hz to 2.00×104 hz . what is range of the wavelengths of
BabaBlast [244]
Given:
f1 = 20 Hz 
f2 = 20000 Hz
speed of sound at 20 degrees celcius = 343 m/s

Solution:

for f1 = 20 Hz,

Using the equation:

lambda = speed of sound / f1 = 343 / 20 = 17.15 m 

For f2: 

lambda = speed of sound / f2 = 343 / 20000 = 0.01775 m

Therefore the wavelength range of audible sound in air would be 17.15 m to 0.01775 m.
6 0
3 years ago
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A wave with a frequency of 60.0 Hz travels through rubber with a wavelength of .90 m. What is the speed of this wave?
gizmo_the_mogwai [7]

Answer:

Speed of wave 54 ms⁻¹.

Explanation:

Given data:

Frequency of wave = 60 Hz

Wavelength of wave = 0.90 m

Speed = ?

Solution:

Formula

speed = wavelength × frequency

Now we will put the values in formula.

v = f × λ

Hz =  s⁻¹

v = 60 s⁻¹ × 0.90 m

v = 54 m s⁻¹

5 0
3 years ago
There is a potential difference of 1.1 V between the ends of a 10 cm long graphite rod that has a cross-sectional area of 0.90 m
Serga [27]

Explanation:

It is given that,

Potential difference between the ends of a rod, V = 1.1 V

Length of the rod, l = 10 cm = 0.1 m

Area of cross section of the rod, A=0.9\ mm^2=9\times 10^{-7}\ m^2

The resistivity of graphite, \rho=7.5\times 10^{-6}\ \Omega-m

(a) Let R is the resistance of the rod. It is given by :

R=\rho \dfrac{l}{A}

R=7.5\times 10^{-6}\times \dfrac{0.1}{9\times 10^{-7}}

R=0.833\ \Omega

So, the resistance of the rod is 0.833 ohms.

(b) Let I is the current flowing in the wire. It can be calculated using the Ohm's law as :

I=\dfrac{V}{R}

I=\dfrac{1.1\ V}{0.833\ \Omega}

I = 1.32 A

(c) Let E is the electric field inside the rod. The electric field in terms of potential difference is given by :

E=\dfrac{V}{l}

E=\dfrac{1.1\ V}{0.1\ m}

E = 11 V/m

Hence, this is the required solution.

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The awnser is C. yogurt
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