Answer:
Observed time, t = 5.58 s
Explanation:
Given that,
Speed of light in a vacuum has the hypothetical value of, c = 18 m/s
Speed of car, v = 14 m/s along a straight road.
A home owner sitting on his porch sees the car pass between two telephone poles in 8.89 s.
We need to find the time the driver of the car measure for his trip between the poles. The relation between real and observed time is given by :
t is observed time.
So, the time observed by the driver of the car measure for his trip between the poles is 5.58 seconds.
Answer:
10 m/s²
Explanation:
Force is the product of mass of an object and its acceleration
The formula is : F= m*a -----where m is mass and a is acceleration
Use the values given in the equation as;
F= m*a
1000 = 100 * a
1000/100 = a
10 = a
10 m/s² = a
Answer
given,
length of the track = 200 m
speed of runner 1 = 6.20 m/s
speed of the runner 2 = 5.5 m/s
distance covered by the fastest runner, d = 6.2 t
distance covered by the slow runner,d = 5.50 t + 200
time taken to overtake for the first time
6.2 t = 5.50 t + 200
0.7 t = 200
t = 285.7 s
distance covered from the starting point
d = 6.2 t
d = 6.2 x 285.7
d = 1771.43 m
for next overtaking time taken will be double
t' = 258.7 x 2 = 571.4 s
distance travel by the runner from the starting point
d' = 6.2 t'
d' = 6.2 x 571.4
d' = 3542.68 m
<span>Orbital radius would decrease because the gravitational pull would increase.</span>