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jeka57 [31]
3 years ago
11

Where does fission regularly occur and what kind of energy is produced?

Physics
2 answers:
WARRIOR [948]3 years ago
6 0
Which one are you talking about bc there's a couple
MissTica3 years ago
6 0
The answer is....

Fission occurs in a nuclear power plant. The energy produced comes in the form of heat.

have a great day!!!


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Plsss help jdybgdykhbskyhdigbjs
Marta_Voda [28]
<h2>ANSWER: </h2><h2>_____________________________________</h2><h2>TYPES OF CHEMICAL REACTIONS:</h2>

There are two types of Reactions,

<h3>Endothermic Reactions: </h3>

Endothermic reactions are the type chemical reaction in which the reactants absorb heat energy from the surroundings. The energy of reactants is more than the energy of product

<h3>Exothermic Reactions: </h3>

Exothermic reactions are the type of chemical reactions in which release of energy takes place in the form of heat or light. In an exothermic reaction, energy is released. The energy of the products is less than the energy of the reactants.

<h2>_____________________________________</h2><h3 /><h3>In Question number 5,</h3>

The key word is "RELEASE". The reaction in which energy is released is the Exothermic reaction thus the Option B that is EXOTHERMIC REACTION is correct.

<h2>_____________________________________</h2><h3 /><h3>In Question number 6</h3>

It is asking that which process stores the energy that means it is asking which process undergoes endothermic reaction. The answer is Option C that is PHOTOSYNTHESIS is correct.

<h3>__________________________________________________</h3><h3>WHY PHOTOSYNTHESIS?</h3>

Because, sunlight is being absorbed during the reaction and according to the definition of endothermic reaction if heat is being absorbed it is termed as an endothermic reaction.

<h3>__________________________________________________</h3><h3 /><h3 />
7 0
3 years ago
Read 2 more answers
Asap. I need an explanaton to how this works as well
bazaltina [42]

Answer:

B: Electrical - Heat

C: Electrical - kinetic

Explanation:

When the hair dryer is plugged to electric supply, electrical energy is converted into heat. When this electricity is circulated through a resistor, heat is now created in the form of losses which make the air around the resistors to be heated.

After that process, this electricity turns into kinetic energy because it forms Electric energy which moves the fan in order to create a flow with the air that's heated.

5 0
3 years ago
Steam enters a long, horizontal pipe with an inlet diameter of D1 = 16 cm at 2 MPa and 300°C with a velocity of 2.5 m/s. Farther
polet [3.4K]

Answer:

m = 0.4005 kg/s

Q_out = 45.1 KJ/s

Explanation:

Given

Pipe inlet diameter D1 = 16 cm

Steam inlet pressure P1 = 2 Mpa

Steam inlet temperature T1 = 300 °C

Pipe outlet diameter D2 = 14 cm

Steam inlet velocity V1 = 2.5 m/s

Steam outlet pressure P2 = 1.8 MPa

Steam outlet temperature T2 = 250 °C  

Required

Determine

(a) The mass flow rate of steam.

(b) The rate of heat transfer.  

Assumptions

Kinetic and potential energy changes are negligible.

This is a steady flow process.

There is no work interaction.  

Solution

Part a From steam table (A-6) at P1 = 2 Mpa , T1 = 300 °C

vl = 0.12551 m^3/Kg

h1 = 3024.2 KJ/Kg

The mass flow rate of steam could be defined as the following  

m = 1/v1*A1*V1

m = 0.4005 kg/s

Part b We take the pipe as our system.The energy balance could be defined as the following  

E_in -E_out =ΔE_sys = 0

E_in = E_out

mh_1 = Q_out + mh_2

Q_out = m(h_1-h_2)

From steam table (A-6) at P2= 1.8 Mpa T2 = 250 °C  h2= 2911.7 KJ/Kg The heat transfer could  be defined as the following

Q_out = m(h_1-h_2)

Q_out = 0.4005*(3024.2 -2911.7) =45.1 KJ/s

6 0
3 years ago
A section of a sphere has a radius of curvature of 0.72 m. If this section is painted with a reflective coating on both sides, w
vaieri [72.5K]

Answer:

The value is  f = 0.36 \  m

Explanation:

From the question we are told that

  The radius of curvature is  R =  0.72 \  m

   

Generally the radius of curvature is mathematically represented as

        R  =  2f

Here f is the focal length hence

       f =  \frac{R}{2}

=>     f =  \frac{0.72}{2}

=>     f = 0.36 \  m

3 0
3 years ago
Two identical parallel plate capacitors A and B connected to a battery of V volts w/ the switch S closed. The switch is now open
Basile [38]
The electrostatic energy stored in a capacitor with capacitance C_0, with a voltage difference V applied to it, and without dielectric, is given by
U_0 =  \frac{1}{2} C_0 V^2
Now let's assume we fill the space between the two plates of the capacitor with a dielectric with constant k. The new capacitance of the capacitor is
C_k = k C_0
So, the energy stored now is
U_k =  \frac{1}{2}C_k V^2= \frac{1}{2}kC_0 V^2

Therefore, the ratio between the energies stored in the capacitor before and after the introduction of the dielectric is
\frac{U_k}{U_0}= \frac{ \frac{1}{2}kC_0 V^2 }{ \frac{1}{2} C_0 V^2}=  k
5 0
3 years ago
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