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Margarita [4]
3 years ago
13

A client has developed dystrophic calcification as a result of macroscopic deposition of calcium salts. The tissue that would be

most affected would be?
Physics
1 answer:
Komok [63]3 years ago
4 0

Answer:

Tissues that are damaged or injured.

Explanation:

Dystrophic calcification involves the deposition of calcium in soft tissues despite no disturbance in the calcium metabolism, and this is often seen at damaged tissues.

Examples of areas in the body where dystrophic calcification can occur include atherosclerotic plaques and damaged heart valves.

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Please select the word from the list that best fits the definition
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Answer:

Neutrons

Explanation:

<em>Protons</em> and <em>neutrons</em> make up the nucleus of the atom

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3 years ago
Choose the correct association for: dense bushes<br><br> savanna<br> rain forest or jungle
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Answer:

Climate is determined by averaging the seasonal weather conditions for a region over a period of many ______ years

Choose the correct association for: dense bushes rain forest or jungle

Choose the correct association for: plains savanna

3 0
3 years ago
suppose an electrically charged ruler transfers some of its charge by contact to a tiny plastic sphere. will the ruler and the s
poizon [28]

Answer:

Here ball and rod will repel each other as they are of similar charges

Explanation:

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F = \frac{kq_1q_2}{r^2}

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5 0
3 years ago
Carlos wanted to know how positive and
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Answer:

it Give only one of them a positive or negative charge

5 0
3 years ago
Read 2 more answers
Student 1 lifts a box with a force of 500 N and sets it on a tabletop 1.2 m high. Student 2 pushes an identical box up a 5 m ram
Troyanec [42]

The student who did the most work is student 2 with 2500 Joules.

<u>Given the following data:</u>

  • Force 1 = 500 Newton
  • Distance 1 = 1.2 meter
  • Force 2 = 500 Newton
  • Distance 2 = 5 meter

To determine which of the students did the most work:

Mathematically, the work done by an object is given by the formula;

Work\;done = Force \times distance

<u>For </u><u>student 1</u><u>:</u>

Work\;done = 500 \times 1.2

Work done = 600 Joules

<u>For </u><u>student 2</u><u>:</u>

Work\;done = 500 \times 5

Work done = 2500 Joules.

Therefore, the student who did the most work is student 2 with 2500 Joules.

Read more: Read more: brainly.com/question/13818347

7 0
3 years ago
Read 2 more answers
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