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shepuryov [24]
3 years ago
10

A fully loaded, slow-moving freight elevator has a cab with a total mass of 1500 kg, which is required to travel upward 57 m in

1.8 min, starting and ending at rest. The elevator's counterweight has a mass of only 840 kg, so the elevator motor must help pull the cab upward. What average power is required of the force the motor exerts on the cab via the cable?
Physics
1 answer:
Kazeer [188]3 years ago
8 0

Answer:

Explanation:

it equals16 2211

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The answer to this question is 3.69
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Compute the dot product of the vectors u and v​, and find the angle between the vectors. Bold v equals 7 Bold i minus Bold j and
OLga [1]

Answer:

\theta = 106.3 degree

Explanation:

As we know that

\vec w = -\hat i + 7\hat j

\vec v = 7\hat i - \hat j

also we know that

\vec v. \vec w = -14

it is given as

\vec v. \vec w = (-\hat i + 7\hat j).(7\hat i - \hat j)

\vec v. \vec w = - 7 - 7 = -14

also we can find the magnitude of two vectors as

|v| = \sqrt{(-1)^2 + (7)^2}

|v| = \sqrt{50}

similarly we have

|w| = \sqrt{(7^2) + (-1)^2}

|w| = \sqrt{50}

now we know the formula of dot product as

\vec v. \vec w = |v||w| cos\theta

-14 = (\sqrt{50})^2cos\theta

\theta = cos^{-1}(\frac{-14}{50})

\theta = 106.3 degree

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2 years ago
Num determinado equipamento industrial, um líquido de calor específico 0,50 cal/g.°C, entra a 20 °C e sai a 80 °C. Se a vazão de
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Explanation:

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Explanation:

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A vector points -43.0 units
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Answer:

Explanation:

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