Answer:
Start running and start to exercise
Explanation:
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Answer:
F=(-4.8*10^22,0,0) N
Explanation:
<u>Given :</u>
We are given the magnitude of the momentum of the planet and let us call this momentum (p_now) and it is given by p_now = 2.60 × 10^29 kg·m/s. Also, we are given the force exerted on the planet F = 8.5 × 10^22 N. and the angle between the planet and the star is Ф = 138°
Solution :
We are asked to find the parallel component of the force F The momentum here is not constant, where the planet moving along a curving path with varying speed where the rate change in momentum and the force may be varying in magnitude and direction. We divide the force here into two parts: a parallel force F to the momentum and a perpendicular force F' to the momentum.
The parallel force exerted to the momentum will speed or reduce the velocity of the planet and does not change its moving line. Let us apply the direction cosines, we could obtain the parallel force as next
F=|F|cosФp (1)
Where the parallel force F is in the opposite direction of p as the angle between them is larger than 90°. Now we can plug our values for 0 and I F I into equation (1) to get the parallel force to the planet
F=|F|cosФp
=-4.8*10^22 N*p
<em>As this force is in one direction, we could get its vector as next </em>
F=(-4.8*10^22,0,0) N
F=(0,-4.8*10^22,0) N
F=(0,0-4.8*10^22) N
The cosine of 138°, the angle between F and p is, is a negative number, so F is opposite to p. The magnitude of the planet's momentum will decrease.
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Density of cylinder is 4.82 g/cm³.
<h3>What is density of a substance?</h3>
Density is the ratio of the mass and the volume of a substance
The density of the cylinder is:
mass of cylinder = 50.12 g
volume of cylinder = πr²h
r = 1.62/2 = 0.81 cm
h = 5.04 cm
volume of cylinder = 22/7 * 0.81² * 5.04
volume of cylinder = 10.39 cm³
Density of cylinder = 50.12 g/10.39 mL
Density of cylinder = 4.82 g/cm³
In conclusion, density of a substance is the ratio of mass and volume of the substance.
Learn more about density at: brainly.com/question/1354972
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