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Lena [83]
3 years ago
12

What is the acceleration of a baseball that has a final velocity of 15.0 m/s when it crosses the plate 2.0 seconds after leaving

the pitchers hand? The initial velocity is 0.0 m/s and the baseball is traveling forward.
Physics
1 answer:
Leokris [45]3 years ago
3 0
I think it’s A pretty sure...
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The quantity of charge q (in coulombs) that has passed through a surface of area 2.00 cm2 varies with time
Makovka662 [10]

Explanation:

We have,

Surface area, A=2\ cm^2=0.0002\ m^2

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q(t) = 4t^3 + 5t + 6

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q(t) = 4t^3 + 5t + 6\\\\q(2) = 4(2)^3 + 5(2) + 6\\\\q=48\ C

(b) Current is given by :

I=\dfrac{dq}{dt}\\\\I=\dfrac{d(4t^3 + 5t + 6)}{dt}\\\\I=12t^2+5

Instantaneous current at t = 1 s is,

I=12(1)^2+5=17\ A

(c) Current is, I=12t^2+5

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Therefore, it is the required explanation.

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