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4 years ago

Jenna built a completed electrical circuit. Jenna’s circuit illustrates what energy transformation?

Physics

2 answers:

Fiesta28 [93]4 years ago

5 0

Answer: The correct answer is D.

Explanation:

In the given problem, Jenna built a completed electrical circuit. From the given circuit diagram, it can be concluded that the electrical energy can be transformed into both heat and light.

The electrical energy is used to light bulb and some of the energy is lost due to heat dissipation.

The wires will get heated up and after some time, the bulb will also get heated up. There is a dissipation of the electrical energy in the form heat.

Therefore, the correct answer is D.

lana [24]4 years ago

3 0

The answer is D. Electrical energy can be transformed into both heat and light.

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A flutist assembles her flute in a room where the speed of sound is 342m/s . When she plays the note A, it is in perfect tune wi

USPshnik [31]

Answer:

a.3Hz

b.0.0034m

Explanation:

First, we know the flute is an open pipe, because open pipe as both end open and a close organ pipe as only one end close.

The formula relating the length and he frequency is giving as

$f=\frac{nv}{2l}\\$ .

a.we first determine the length of the flute at the fundamental frequency i.e when <em>n</em>=1 and when the speed is in the 342m/s

Hence from

$f=\frac{nv}{2l}\\\\l=\frac{342}{2*440}\\ l=0.389m\\$ .

since the value of the length will remain constant, we now use the value to determine the frequency when the air becomes hotter and the speed becomes 345m/s.

$f=\frac{nv}{2l} \\f=\frac{345}{2*0.389}\\f=443.4Hz$

Hence the require beat is

$B=/f_{1}-f_{2}/\\B=/440-443/\\B=3Hz$ .

b. since the length is dependent also on the speed and frequency, we determine the new length when she plays with a fundamental frequency when the speed of sound is 345m/s

using the formula

$L_{new}=\frac{v}{2f}\\\\L_{new}=\frac{345}{2*440}\\\\L_{new}=0.39204$

Now to determine the extension,

$L_{extend}=L_{new}-L_{old}\\L_{extend}=0.39204- 0.38864\\L_{extend}=0.0034m\\$

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