Trigonometry Help, question posted below @AL2006

Physics

1 answer:

Oxana [17]3 years ago

8 0

It's ' D '.

-- Period: The angle is (pi/2 · t).
From t=0 to t=4 sec, the angle changes by 2pi. So the period is 4 sec.

-- Amplitude: The biggest the cosine can ever be is 1 .
When the cosine part is 1, 'd' is 6, so the amplitude of the model is 6 .

-- Position when t=0:
When t=0, the angle in the cosine is zero.
The cosine of zero is 1 .
So when t=0, d=6 . There you are.

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A 0.050 kg bullet strikes a 5.0 kg stationary wooden block and embeds itself in the block. The block and the bullet fly off toge

natka813 [3]

Answer: 909 m/s

Explanation:

Given

Mass of the bullet, m1 = 0.05 kg

Mass of the wooden block, m2 = 5 kg

Final velocities of the block and bullet, v = 9 m/s

Initial velocity of the bullet v1 = ? m/s

From the question, we would notice that there is just an object (i.e the bullet) moving before the collision. Also, even after the collision between the bullet and wood, the bullet and the wood would move as one object. Thus, we would use the conservation of momentum to solve

m1v1 = (m1 + m2) v, on substituting, we have

0.05 * v1 = (0.05 + 5) * 9

0.05 * v1 = 5.05 * 9

0.05 * v1 = 45.45

v1 = 45.45 / 0.05

v1 = 909 m/s

Thus, the original velocity of the bullet was 909 m/s

3 0

3 years ago

Students are given the following information about a 2.0 kg, motorized toy boat on water. what net force is exerted on the boat

Natasha_Volkova [10]

The motorized toy boat experiences a net force of 0 N between 4 s and 8 s.

The motorized toy boat moves at 8 m/s (u) at 4 s and at 8 m/s (v) at 8 s. We can calculate the acceleration (a) in that period using the following kinematic expression.

$a = \frac{v-u}{\Delta t} = \frac{8m/s-8m/s}{8s-4s} = 0 m/s^{2}$

The object with a mass (m) of 2.0 kg experiences an acceleration of 0 m/s². We can calculate the net force (F) in that period using Newton's second law of motion.

$F = m \times a = 2.0 kg \times 0 m/s^{2} = 0 N$

The motorized toy boat experiences a net force of 0 N between 4 s and 8 s.

Learn more: brainly.com/question/13447525

6 0

2 years ago

A raccoon falls out of a tree from a height of 1.2. Which equation can you use to calculate the time it takes for the raccoon to

Inga [223]

Answer:

$t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2 \cdot 1.2 m}{9.81 m/s^2}}=0.50 s$

Explanation:

The equation that we can use to calculate the time it takes for the raccoon to fall to the ground is:

$t=\frac{2S}{g}$

where S=1.2 m is the height of the tree and g=9.81 m/s^2 is the acceleration due to gravity. This equation is derived from the equation of the distance in a uniformly accelerated motion, which is given by

$S=S_0 + v_0 t + \frac{1}{2}at^2$

where S0 is the initial position, v0 is the initial velocity and t the time. In this problem, we can put S0=0 (we can take the initial position as the initial position of the raccoon) and v0=0 (the raccoon starts from rest), so the equation becomes

$S=\frac{1}{2}at^2$