Answer by JKismyhusbandbae:
|x| - 2 > 0
|x| -2 + 2 > 0 + 2
|x| > 2
Answer: x < - 2 or x > 2
Answer:
Area is 10x^2 - 4x + 6
Step-by-step explanation:
To find this area, multiply the width and height together:
(5x^2 - 2x + 3)(2) = 10x^2 - 4x + 6
My answer is the 2nd option.
Without changing the compass setting from the previous step, place the compass on point P. Draw an arc similar to the one already drawn.
Parallel lines are lines that do not meet. In this figure, point P is the point where the 2nd line can be drawn and become parallel to line AB.
5x^3+8x^2/3x^4-16x^2=x^2(5x+8)/x^2(3x^2-16)=5x+8/3x^2-16
lim x--->0 5x+8/3x^2-16=8/-16=-1/2
