Answer:
Elements form compounds to satisfy the octet rule. Noble gasses never form compounds because they already satisfy the octet rule.
Explanation:
The octet Rule is the theory that an element will attempt to gain a valence of 8 by binding with another element in it's vicinity. This can happen in a variety of ways, but the main thing to remember is that they will take the "shortest path" to 8(I.e an element will sometimes lose an electron or 2 if it has a valence 1 or 2 to loop back around to 8, while an element with a valence of 6 or 7 will attempt to gain 2 or 1 electrons).
Valence of elements can be counted by group in the image attached.
Group 1 has a valence of 1, Group 2 has a valence of 2, then we move to group 13 which has a valence of 3, group 14 has a valence of 4, group 15 has a valence of 5, group 16 has 6, group 17 has 7, and group 18 is the noble gasses which have 8.
Answer:
The answer to your question is 6
Explanation:
Data
Cu + 2AgNO₃ ⇒
To find the answer, count the number of each element in the reactants
Element Quantity
Copper 1
Silver 2
Nitrogen 1
Oxygen 6
Then, in the products, there must be 6 oxygens so in the products there must be 6 oxygens so the reaction is balanced.
Answer : The value of
is -49.6 kJ/mol
Explanation :
First we have to calculate the reaction quotient.
Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.
The given balanced chemical reaction is,

The expression for reaction quotient will be :
![Q=\frac{[ADP][HPO_4^{2-}]}{[ATP]}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BADP%5D%5BHPO_4%5E%7B2-%7D%5D%7D%7B%5BATP%5D%7D)
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.
Given:
= 5.0 mM
= 0.60 mM
= 5.0 mM
Now put all the given values in this expression, we get

Now we have to calculate the value of
.
The formula used for
is:
............(1)
where,
= Gibbs free energy for the reaction = ?
= standard Gibbs free energy = -30.5 kJ/mol
R = gas constant = 
T = temperature = 
Q = reaction quotient = 
Now put all the given values in the above formula 1, we get:


Therefore, the value of
is -49.6 kJ/mol
Answer:
About 0.566 L.
Explanation:
Let the substance be represented by <em>X</em>.
We want to determine how much volume in L will 8,326 dg (decigrams) of the substance which has a density of 1.47 g/mL occupy.
To convert from 8,326 dg to L, we can first convert from dg to g, g to mL using the density, and mL to L.
Recall that 1 g = 10 dg and 1 L = 1000 mL. We are also given that the density of <em>X</em> is 1.47 g/mL. This yields three ratios:

Starting with the initial value, multiply:

Hence, 8,326 dg of the substance occupies about 0.566 L.
Answer:
· Litter loss triggers estrus in a nonsocial seasonal breeder
Explanation: