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AlekseyPX
3 years ago
10

Instructions:Select the correct answer. A certain skin lotion is a fine mixture of water and various oils. This lotion is cloudy

and cannot be separated into oil and water by filtration. Moreover, its components do not separate when left standing. What type of mixture is it?
Chemistry
1 answer:
olga2289 [7]3 years ago
6 0
<span>What type of mixture is it:
Colloid </span>
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Spindle fibers break down during what phase?
Rasek [7]
Answer: Prophase.
In prophase, chromosomes condense and become visible. Spindle fibers emerge from the centrosomes.
7 0
3 years ago
Read 2 more answers
Ammonium Iodide dissociates reversibly to ammonia and hydrogen iodide:
NeTakaya

Answer:

The partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C Is 0.103 atm.

The correct option is A.

Explanation;

NH4I(s) ⇋ NH3(g) + HI(g)Kp = 0.215 at 400°C

NH4I(s)= 0.215

NH3(g)=0.103

HI(g)Kp=0.112

Therefore = 0.103 +0.112= 0.215

Therefore the partial pressure of ammonia at equilibrium is 0.103 atm

7 0
3 years ago
A beach ball has a mass of 5 g and a volume of 20 cm3. What is the object's density?
ivann1987 [24]
Mass = 5 g

volume = 20 cm³

density = mass / volume

therefore:

D = m / V

D = 5 / 20

D = 0.25 g/cm³
3 0
3 years ago
In this prelab exercise, you will calculate how to prepare solutions that you will make in lab. Below is an example of how to pr
Anastasy [175]

Explanation:

Molarity=\frac{\text{Moles of compound}}{\text{Volume of solution (L)}}

Moles of compound =

\frac{\text{mass of compound}}{\text{Molar mass of compound}}

We have ;

Volume of solution = 600 mL = 0.600 L ( 1 mL = 0.001 L)

Moles of NaOH = n

Molarity of the solution = 3 M

3M=\frac{n}{0.600 L}

n = 3 M × 0.600 L = 1.800 mol

Mass of 1.800 mole sof NaOH :

1.800 mol × 40 g/mol = 72.0 g

Preparation:

Weight 72.0 grams of sodium hydroxide and add it to the 500 mL of volumetric flask along with some water. Dissolve the all the solute by adding small proportion of water. After the solution becomes clear make the water upto the mark of 500 ml.

Transfer the solution to a bigger beaker  and 100 mL of water more to it.

6 0
3 years ago
To make 2.00 L of 0.300 M sulfuric acid, how many mL of a 1.00 M stock solution should be used?
Tamiku [17]
We are given with
M1 = 1.00 M

M2 = 0.300 M
V2 = 2.00 L

We are asked to get V1

Using material balance
M1 V1 = M2 V2
Substituting the given values
1.00 V1 = 0.300 M (2.00 L)
V1 = 0.600 L or 600 mL
THe volume needed is 600 mL<span />
3 0
3 years ago
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