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AveGali [126]
3 years ago
7

Account for the difference in the masses of coke and diet coke

Chemistry
1 answer:
nignag [31]3 years ago
6 0

Answer:

regular Coke is denser than diet Coke. Each can of regular Coke has a mass of about 384 g. and diet coke has about 370 g.

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Which best compares a molecule that has a trigonal planar shape with one that has a trigonal pyramidal shape?
Juli2301 [7.4K]

Answer:

B. They both contain three atoms around the central atom.

Explanation:

Do the unit test on edg20 and got it right!

7 0
3 years ago
Conducting a monohybrid cross of F1 generation plants, the recessive trait reappears in F2 plants in a ratio of _____.
lisabon 2012 [21]

the answer is 3:1

hope this helps

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8 0
3 years ago
BRAINLIESTTT ASAP!!! PLEASE HELP ME :)
SCORPION-xisa [38]

Every science experiment should follow the basic principles of proper investigation so that the results presented at the end are seen as credible.

Observation and Hypothesis. ...

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4 0
3 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m
Bond [772]

Answer:

m_{H_2O}=4.86gH_2O

Explanation:

Hello,

In this case, the described chemical reaction is:

C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O

Best regards.

3 0
3 years ago
14
Bond [772]

Answer:

Explanation:

The melting point of a substance is the temperature at which its melt. The state of a substance is dependent on it's melting temperature. Generally, melting point above 25 °C is a solid.

This means phenol is a solid

Duodecane has melting point below 25 °C hence it is either a liquid or gas. However its boiling point of 216 °C means it would require higher temperature to boil it. Since 25 °C is less than 216 °C it means that it would remain in the liquid state.

Methane has melting point below 25 °C hence it is either a liquid or gas. However its boiling point of -164 °C means it boils easily even at very low temperatures. Since 25 °C is greater than -164 °C it means that it would exist in the gaseous state

8 0
3 years ago
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