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Vlada [557]
3 years ago
5

Describe two hazards identified with hydrochloric acid?

Chemistry
1 answer:
DerKrebs [107]3 years ago
8 0
Frostbite to the skin and Severe burning to the eyes.
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Arrange the following elements from greatest to least tendency to accept an electron.? Rank from greatest to least tendency to a
shtirl [24]
Your answer is correct, I do not understand why it would be wrong.
The electron accepting tendency of an atom is known as the tendency of an atom to accept an electron. This is ranked on a scale of 0.7 to 3.98 and these species have the following values:
F: 3.98
O: 3.44
C: 2.55
Be: 1.57
Li: 0.98
3 0
3 years ago
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Static charges can be applied to neutral objects by friction, induction or conduction. What do all of these methods utilize to c
MatroZZZ [7]
Electrons are valence and free moving so they take place in charge transfer
5 0
3 years ago
How far apart must two point charges of 75.0 nC (typical of static electricity) be to have a force of 1.00 N between them? (answ
Jet001 [13]

Answer:

7.12 mm

Explanation:

From coulomb's law,

F = kqq'/r².................... Equation 1

Where F = force, k = proportionality constant, q and q' = The two point charges, r = distance between the two charges.

Make r the subject of the equation,

r = √(kqq'/F).......................... Equation 2

Given: q = q' = 75.0 nC = 75×10⁻⁹ C, F = 1.00 N

Constant: k = 9.0×10⁹ Nm²/C².

Substitute into equation 2

r = √[ (75×10⁻⁹ )²9.0×10⁹/1]

r = 75×10⁻⁹.√(9.0×10⁹)

r = (75×10⁻⁹)(9.49×10⁴)

r = 711.75×10⁻⁵

r = 7.12×10⁻³ m

r = 7.12 mm

Hence the distance between the point charge = 7.12 mm

3 0
3 years ago
True or false?<br><br> When sodium and chlorine combine and bond, a molecule is formed.
CaHeK987 [17]

When Sodium and Chlorine come together they transfer an electron.

- Source: google


Hopefully this was clear and you understood!

3 0
3 years ago
Hi May I know how to balance this
almond37 [142]

Answer:

  2Ba₃(PO₄)₂ +6SiO₂ ⇒ P₄O₁₀ +6BaSiO₃

Explanation:

Equating coefficients, you get ...

  aBa₃(PO₄)₂ +bSiO₂ ⇒ cP₄O₁₀ +dBaSiO₃

For Ba: 3a = d

For P: 2a = 4c

For O: 8a +2b = 10c +3d

For Si: b = d

__

Expressing everything in terms of b and c, we get ...

  d = b

  a = b/3 = 2c

From the second, b = 6c, so we have ...

  a = 2c

  b = 6c

  c = c

  d = 6c

And we can write the equation with c=1 as ...

  2Ba₃(PO₄)₂ +6SiO₂ ⇒ P₄O₁₀ +6BaSiO₃

4 0
3 years ago
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