The rule for multiplying similar bases with exponents is:
(a^b)*(a^c)=a^(b+c)
In this case you have:
(x^9)(x^2)
x^(9+2)
x^11
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
D. -15
All I did was plug the numbers in
Answer:
I don't think any are a correct graph of the function. But here are the ordered pairs. (1,0),(0,-2),(-1,-4)
Step-by-step explanation:
Take three values for x and plug them in for your y's. For instance x values of 1,0,-1. Plug each in to find the y value. 2(1) - 2 =y so (1,0)
D(X+2)(2X+1) This is your answer.
