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mariarad [96]
4 years ago
9

what is the chemical equation for the burning of propane if all the products and reactants are in the gas phase

Chemistry
2 answers:
Dima020 [189]4 years ago
7 0

Answer:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

Explanation:

Orlov [11]4 years ago
3 0

Answer:

The correct chemical equation is:

C3H8(g) + 5O2(g)----> 3CO2(g) + 4H2O(g)

Explanation:

In the presence of excess oxygen, propane burns to form water and carbondioxide. Propane burns with a visible flame.

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A student obtains the following data: Mass of empty, dry graduated cylinder: 21.577 g Volume added of NaCl solution: 4.602 mL Ma
klasskru [66]

<u>Answer:</u> The density of NaCl solution is 3.930 g/mL

<u>Explanation:</u>

We are given:

Mass of cylinder, m_1 = 21.577 g

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Mass of NaCl, m_2 = (M-m_1)=(39.664-21.577)g=18.087g

To calculate density of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

We are given:

Mass of NaCl = 18.087 g

Volume of NaCl solution = 4.602 mL

Putting values in above equation, we get:

\text{Density of NaCl}=\frac{18.087g}{4.602mL}\\\\\text{Density of NaCl}=3.930g/mL

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