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3 years ago

what is the chemical equation for the burning of propane if all the products and reactants are in the gas phase

Chemistry

2 answers:

Dima020 [189]3 years ago

7 0

Answer:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

Explanation:

Orlov [11]3 years ago

3 0

Answer:

The correct chemical equation is:

C3H8(g) + 5O2(g)----> 3CO2(g) + 4H2O(g)

Explanation:

In the presence of excess oxygen, propane burns to form water and carbondioxide. Propane burns with a visible flame.

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A solution is created by dissolving 11.5 grams of ammonium chloride in enough water to make 255 mL of solution. How many moles o

Nata [24]

Answer:

<h2>The no. of moles present in one liter solution is 0.843</h2>

Explanation:

Mass of ammonium chloride = 11.5 gm

Molar mass of ammonium chloride = 53.491 gm

No. of moles

$N = \frac{mass}{molar \ mass}$

$N = \frac{11.5}{53.491}$

N = 0.215 moles

$Molarity= \frac{N}{volume}$

$molarity = \frac{0.215}{0.255}$

M = 0.843 M

Thus the no. of moles present in one liter solution is 0.843

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3 years ago

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yuradex [85]

It requires the allocation of resources.

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2 years ago

Can you help me with scientific tools because I'm struggling and this is 90% of my grade

weqwewe [10]

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3 years ago

What is the main purpose of using NaOH in the saponification reaction . NaOH works as the catalyst b. NaOH solution is the solve

Alex777 [14]

Answer:

C. NaOH acts as a reactant in the reaction

Explanation:

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7 0

3 years ago

What volume of oxygen (in L) is produced

sveticcg [70]

Answer:

12.36 L.

Explanation:

We'll begin by calculating the number of mole in 147.1 g of lead(II) nitrate, Pb(NO₃)₂. This can be obtained as follow:

Molar mass of Pb(NO₃)₂ = 207.2 + 2[14.01 + (16×3)]

= 207.2 + 2[14.01 + 48]

= 207.2 + 2[62.01]

= 207.2 + 124.02

= 331.22 g/mol

Mass of Pb(NO₃)₂ = 147.1 g

Mole of Pb(NO₃)₂ =?

Mole = mass / Molar mass

Mole of Pb(NO₃)₂ = 147.1 / 331.22

Mole of Pb(NO₃)₂ = 1.104 moles.

Next, we shall determine the number of mole of oxygen gas, O₂, produce from the reaction. This can be obtained as follow:

2Pb(NO₃)₂ —> 2PbO + 4NO₂ + O₂

From the balanced equation above,

2 moles of Pb(NO₃)₂ decomposed to produce 1 mole of O₂.

Therefore, 1.104 moles of Pb(NO₃)₂ will decompose to produce = (1.104 × 1)/2 = 0.552 mole of O₂.

Finally, we shall determine the volume occupied by 0.552 mole of oxygen gas, O₂. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 0.552 mole of O₂ will occupy = 0.552 × 22.4 = 12.36 L at STP.

Thus, the volume of oxygen gas, O₂ produced is 12.36 L.

6 0

2 years ago