Answer:
The final volume of NaOH solution is 30ml
Explanation:
We all know that
V1S1 = V2S2
or V1= V2S2÷S1
or V1= V2×S2×1/S1
or V1=100×0.15×1/0.50
V1= 30
∴30 ml NaOH solution is required to prepare 0.15 M from 100ml 0.50 M NaOH solution.
The answer is (2). Heat always flows down the temperature gradient, from high temperature to low temperature. Therefore, since the person is the warmest, heat flows from the person to both the ice and the air. Additionally, since the air is warmer than the ice, heat flows from the air to the ice.
Answer:
Explanation:
MnO₂(s) + 4 HCl(aq) = MnCl₂(aq) + 2 H₂O(l) + Cl₂
87 g 22.4 x 10³ mL
volume of given chlorine gas at NTP or at 760 Torr and 273 K
= 175 x ( 273 + 25 ) x 715 / (273 x 760 )
= 179.71 mL
22.4 x 10³ mL of chlorine requires 87 g of MnO₂
179.4 mL of chlorine will require 87 x 179.4 / 22.4 x 10³ g
= 696.77 x 10⁻³ g
= 696.77 mg .
It required a fixed finite amount these zones are known as energy levels
