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2 years ago

Which statement is the best explanation for the graph?

Chemistry

1 answer:

kvv77 [185]2 years ago

8 0

Answer:

The statement that correctly explains the graph attached is: "As temperature rises, gas particles are moving faster and may leave the solution."

We know that the solubility of a gas decreases with increasing temperature. This stems from the fact that the kinetic energy and velocity of gas molecules increases with increase in temperature.

That means that as a the temperature of a gas increases, its molecules move faster and are more likely to escape from solution rather than enter the solution.

This explains the decrease in the solubility of a gas with increase in temperature.

Explanation:

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Use the atomic mass of indium to calculate the relative abundance of indium-113.

ASHA 777 [7]

The relative abundance of indium-113 is 4%.

The isotopes are species of the same element having the same atomic number but a different mass number.

The elements occurring in nature exist as multiple isotopes.

When we take into account the existence of these isotopes and their relative abundance (percent), the average atomic mass of that element can be computed, which is given by the following formula,

Average atomic Mass= (%age of isotope 1) x (Mass of isotope 1) + (%age of isotope 2) x (Mass of isotope 2)/100

Indium exists in the form of Indium-113 and Indium-115.

The mass of Indium-113 is 112.90 u.

The mass of Indium-115 is 114.90 u.

The average atomic mass of Indium is 114.82 u.

Let the %age of isotope 1(Indium-113) be X.

Then, the %age of isotope 2(Indium-115) would be 100-X.

Applying the values in the formula,

Average atomic mass = 112.90X+114.90(100-X)

114.82 = 112.90X+114.90(100-X)

On solving the above equation, the value of X comes out to be 4%.

Thus, the relative abundance/%age abundance of Indium-113 is 4%.

To know more about "Average Atomic Mass", refer to the following link:

brainly.com/question/13753702?referrer=searchResults

#SPJ4

7 0

1 year ago

The enthalpy of a pure liquid at 75oC is 100 J/mol. The enthalpy of the pure vapor of that substance at 75oC is 1000 J/mol. What

pentagon [3]

Answer:

900 J/mol

Explanation:

Data provided:

Enthalpy of the pure liquid at 75° C = 100 J/mol

Enthalpy of the pure vapor at 75° C = 1000 J/mol

Now,

the heat of vaporization is the the change in enthalpy from the liquid state to the vapor stage.

Thus, mathematically,

The heat of vaporization at 75° C

= Enthalpy of the pure vapor at 75° C - Enthalpy of the pure liquid at 75° C

on substituting the values, we get

The heat of vaporization at 75° C = 1000 J/mol - 100 J/mol

The heat of vaporization at 75° C = 900 J/mol

8 0

3 years ago

In which position are the earth, moon, and sun during a new moon?

RSB [31]

Answer:

They are in this position

4 0

3 years ago

Which of the following is not a chemical property?

malfutka [58]

Density is not a chemical property. It is a physical property.Electromotive force, Flammability and pH are chemical properties.

8 0

3 years ago

A student must make a 3 m acid solution using a 5 m acid solution. which of these is the safest way to make the solution?

weqwewe [10]

The motivation to abstain from adding water to concentrated acids is that, with a few acids, amid weakening, a considerable measure of warmth is discharged, by adding the corrosive to the water, the generally extensive measure of water will retain the warmth. On the off chance that you added water to concentrated corrosive when you initially beginning pouring the water, it could get sufficiently hot for the little measure of water that was filled all of a sudden bubble and splatter corrosive on you. Concentrated sulfuric corrosive is most famous for doing this, not all acids get that hot on weakening, but rather in the event that you make a propensity for continually adding the corrosive to water for every one of them, you can't turn out badly.

8 0

3 years ago