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3 years ago

Breve resumen de que es volumen

Chemistry

1 answer:

andrey2020 [161]3 years ago

4 0

What??? what language is this?

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explain one or two things that adversely (negatively) affect the Earth's environment. How do you know that these things you're d

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Humans impact the physical environment in many ways: overpopulation, pollution, burning fossil fuels, and deforestation. Changes like these have triggered climate change, soil erosion, poor air quality, and undrinkable water.

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3 years ago

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A mixture of 0.307 M Cl 2 , 0.465 M F 2 , and 0.706 M ClF is enclosed in a vessel and heated to 2500 K . Cl 2 ( g ) + F 2 ( g )

monitta

Answer: The equilibrium concentration of chlorine gas, fluorine gas and ClF gas is 0.159 M, 0.317 M and 1.002 M respectively.

Explanation:

We are given:

Initial concentration of chlorine gas = 0.307 M

Initial concentration of fluorine gas = 0.465 M

Initial concentration of ClF gas = 0.706 M

The given chemical equation follows:

$Cl_2(g)+F_2(g)\rightleftharpoons 2ClF(g)$

Initial: 0.307 0.465 0.706

At eqllm: 0.307-x 0.465-x 0.706+2x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[ClF]^2}{[Cl_2][F_2]}$

We are given:

$K_c=20.0$

Putting values in above equation, we get:

$20.0=\frac{(0.706+2x)^2}{(0.307-x)(0.465-x)}\\\\x=0.148,0.993$

Neglecting the value of x = 0.993 because the equilibrium concentrations of chlorine and fluorine gases will become negative, which is not possible

So, equilibrium concentration of chlorine gas = (0.307 - x) = [0.307 - 0.148] = 0.159 M

Equilibrium concentration of fluorine gas = (0.465 - x) = [0.465 - 0.148] = 0.317 M

Equilibrium concentration of ClF gas = (0.706 + 2x) = [0.706 + 2(0.148)] = 1.002 M

Hence, the equilibrium concentration of chlorine gas, fluorine gas and ClF gas is 0.159 M, 0.317 M and 1.002 M respectively.

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3 years ago

What method do all scientists, across all fields, use in the pursuit of scientific

navik [9.2K]

They use experimental investigations where they manipulate variables

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3 years ago

Calculate the density of unknown substance #1 which has a mass of 15.8 grams and a volume of 20 cm3. *

GenaCL600 [577]

Answer:

$\boxed{\sf Density \ of \ unknown \ substance = 0.79 \ g/cm^3}$

Given:

Mass = 15.8 g

Volume = 20 cm³

To Find:

Density of unknown substance

Explanation:

Formula:

$\boxed{ \bold{Density = \frac{Mass}{Volume}}}$

Substituting value of mass & volume in the formula:

$\sf \implies Density = \frac{15.8}{20} \\ \\ \sf \implies Density = 0.79 \: g/cm^3$

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4 years ago