Potassium can be a component of the cream.
<h3>Why does potassium show white-purple flame when burned?</h3>
An element's presence can be determined using a flame test. The potassium in cream of tartar is what gives it its white-purple color.
Low ionization enthalpy elements allow the flame to display color. Due to low ionization enthalpy, when an element is heated, its valence electrons are quickly excited to higher orbits and emit light as they return to their original orbit. Salts of potassium emit a white-purple color when ignited. The cream of tartar's chemical formula is KC₄H₅O₆.
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- Naturally occurring
- Inorganic
- Solid
- Definite chemical composition
- Ordered internal structure
A mineral has to be naturally occurring. Coal is not a mineral because it is carbon-based and comes from fossilized plants. Glass is non-crystalline solid.
Answer:
Line 3 is incorrect
Explanation:
In line 3, the statements should be switched. Chemical reactions involve small amounts of energy and nuclear reactions involve enourmous amounts of energy. Lines 1 and 2 are correct.
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ΔG deg will be negative above 7.27e+3 K.
<u>Explanation:</u>
- The ΔG deg with the temperature can be found using the formula and the formula is given below
- ΔG deg = ΔH deg - T ΔS deg
- Given data, ΔH deg = 181kJ and ΔSdeg=24.9J/K
- -T ΔS deg will be always negative and ΔG deg = ΔH deg will be positive and ΔG deg will be negative at relatively high temperatures and positive at relatively low temperatures
- solving the equation and substitute ΔGdeg=0
- ΔGdeg = ΔHdeg - T ΔSdeg
- T= ΔHdeg/ΔSdeg
- T=181 kJ / 2.49e-2 kJK-1
- By simplification we get
- T=7.27 × 10^3 K.
- Therefore, Go will be negative above 7.27 × 10^3 K
- Since ΔG deg = -RT lnK, when ΔGdeg < 0, K > 1 so the reaction will have K > 1 above 7.27 × 10^3 K.
- ΔG deg will be negative above 7.27e+3 K.
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Answer:
The concentration of nitrate ion
is 0.033 M.
Explanation:

1 mole of
= 3 mole 
Let
= 3y
then according to above reaction,
= y
= 0.10 M (given)
= ?
3y = 0.10 M

y = 0.033 M
So ,concentration of
= y = 0.033 M