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Pachacha [2.7K]
2 years ago
10

Convert 30.0 degrees Celsius into Kelvin

Physics
1 answer:
frutty [35]2 years ago
4 0

Answer:

303.15K

Explanation:

the formula for converting celsius into kelvin is adding 273.15 to the number

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Written accounts, objects, and buildings are examples of the types of evidence that historians and archaeologists study to expla
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     Your answer would be true. Because if we didn't have those pieces of evidence, we wouldn't know about a lot of the ancient civilizations that we know today without that. Small pieces of evidence like that can help us to determine how they lived, or what they used to do, or even what they ate.
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Both Newton's Law of Universal Gravitation and Coulomb's Law follow the ...
Romashka [77]

Answer:

inverse square relationship

Explanation:

Both the Newton's law of universal gravitation and coulomb's law have their force inversely proportion to the square of the distance between the bodies.

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2 years ago
A girl runs 40m due south in 40 seconds an d then 20m due north in 10 secondsCalculate.
m_a_m_a [10]

Answer:

Average speed = 1.2 m/s

Average velocity = 0.4 m/s

Explanation:

Average speed = total distance/total time

Average speed = (40 + 20)/(40 + 10)

Average speed = 60/50

Average speed = 1.2 m/s

Average velocity = displacement/time

Now, she ran 40 m south and ran 20 m back north which is in the direction of where she began the journey.

Thus;

Displacement = 40 - 20 = 20 m

Average velocity = 20/50 = 0.4 m/s

3 0
3 years ago
Physics Question: Determine the work that is being done by tension in pulling the box 193.0 cm along the table. Also determine t
lozanna [386]

1) The work done by tension is 12.0 J

2) The final speed of the box is 1.57 m/s

Explanation:

The work done by a force on an object is given by:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and of the displacement

For the box in this problem, we have:

F = 6.2 N is the force applied (the tension in the string)

d = 193.0 cm = 1.93 m is the displacement

\theta=0 assuming that the string is horizontal

Substituting, we find the work done by the tension:

W=(6.2)(1.93)(cos 0)=12.0 J

2)

In order to determine the final speed of the box, we need to determine its acceleration first.

Beside the tension, acting forward, the other force acting horizontally on the box is the force of friction, whose magnitude is

F_f = \mu mg

where

\mu=0.16 is the coefficient of friction

m = 2.8 kg is the mass of the box

g=9.8 m/s^2 is the acceleration of gravity

Substituting,

F_f = (0.16)(2.8)(9.8)=4.4 N

Therefore, the net force on the box is

F=6.2  N - 4.4 N = 1.8 N

And the acceleration can be found by using Newton's second law:

F=ma

where

F = 1.8 N is the net force

m = 2.8 kg is the mass of the box

a is the acceleration

Solving for a,

a=\frac{F}{m}=\frac{1.8}{2.8}=0.64 m/s^2

Now we can finally find the final speed using the suvat equation:

v^2-u^2=2as

where

v is the final speed

u = 0 is the initial speed

a=0.64 m/s^2 is the acceleration

s = 1.93 m is the displacement

Solving for v,

v=\sqrt{u^2+2as}=\sqrt{0+2(0.64)(1.93)}=1.57 m/s

Learn more about work:

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3 years ago
A ball of mass m kg is rolled up a slope at an angle a to the horizontal, where sin a = 2/5. The ball passes a point A with spee
myrzilka [38]

16.42 seconds will elapse between passing B on the way up and coming back to B on the way down.

<h3>What is the definition of Angular Speed? </h3>

The rate of change of angular displacement is defined as angular speed, and it is stated as follows:

ω = θ t

Where,

θ is the angle of rotation,

t is the time

ω is the angular velocity

Given data;

sin a = 2/5

a=sin(2/5)

a=23°

The linear velocity is the product of the angular velocity and the length.

\rm v= \omega r \\\\ \omega= 7/5 \\\\ \omega= 1.4 \ rad/sec

The times between the two points are found as;

\omega = \frac{\triangle \theta }{\triangle t} \\\\ t= \frac{23}{1.4} \\\\ t = 16.42 \ sec

Hence, the time between passing B on the way up and returning to B on the way down will be 16.42 sec.

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5 0
2 years ago
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