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2 years ago

Cars A and B have the same mass, but Car A's speed is 15 mph, whereas Car B is moving at 60 mph. The kinetic energy

Physics

1 answer:

kupik [55]2 years ago

7 0

Answer:

16 times that of car A

Explanation:

Moving objects have kinetic energy which is calculated using the formula:

E=(1/2)mv² where m is the mass of the object and v is its velocity.

For car A, kinetic energy =1/2×m×15²

=112.5m........................................i

For car B, the kinetic energy =1/2×m×60²

=1800m......................................ii

dividing ii by i we get

1800m/112.5m= 16.07

Therefore The kinetic energy of car B is 16.07 times that of car A

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Verizon [17]

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2 years ago

Read 2 more answers

A 0.20-kg object is attached to the end of an ideal horizontal spring that has a spring constant of 120 N/m. The simple harmonic

Umnica [9.8K]

Answer:

Explanation:

<u>Simple Harmonic Motion</u>

A mass-spring system is a common example of a simple harmonic motion device since it keeps oscillating when the spring is stretched back and forth.

If a mass m is attached to a spring of constant k and they are set to oscillate, the angular frequency of the motion is

$\displaystyle w=\sqrt{\frac{k}{m}}$

The equation for the motion of the object is written as a sinusoid:

$\displaystyle X=A\ cos\ w\ t$

Where A is the amplitude.

The instantaneous speed is computed as the derivative of the distance

$\displaystyle X'=V=-A\ w\ sin\ w\ t$

And the maximum speed is

$\displaystyle V_{max}= A\ w$

Solving for the amplitude

$\displaystyle A= \frac{V_{max}}{w}$

Computing w

$\displaystyle w =\sqrt{\frac{120}{0.2}}=24.5\ rad/ s$

Calculating A

$\displaystyle A=\frac{1.7}{24.5}=0.069\ m$

$\displaystyle \boxed{A=6.9\ cm}$

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3 years ago

As your hand moves back and forth to generate longitudinal pulses in a spiral spring, your hand completes 2.91 back-and-forth cy

Lapatulllka [165]

Answer:

Wavelength, $\lambda=0.011\ m$

Explanation:

Given that,

Number of cycles in a spiral spring is 2.91 in every 3.67 s

The velocity of the pulse in the spring is 0.925 cm/s, v = 0.00925 m/s

To find,

Wavelength

Solution,

Number of cycles per unit time is called frequency of a wave. The frequency of the longitudinal pulse is,

$f=\dfrac{2.91}{3.67}=0.79\ Hz$

The wavelength of a wave is given by :

$\lambda=\dfrac{v}{f}$

$\lambda=\dfrac{0.00925\ m/s}{0.79\ Hz}$

$\lambda=0.011\ m$

So, the wavelength of the longitudinal pulse is 0.011 meters. Hence, this is the required solution.

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2 years ago

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7 0

3 years ago

Read 2 more answers

A wedge with an inclination of angle θ rests next to a wall. A block of mass m is sliding down the plane. There is no friction b

Softa [21]

Answer:

The net force on the block F(net) = mgsinθ).

Fw =mg(cosθ)(sinθ)

Explanation:

(a)

Here, m is the mass of the block, n is the normal force, \thetaθ is the wedge angle, and Fw is the force exerted by the wall on the wedge.

Since the block sliding down, the net force on the block is along the plane of the wedge that is equal to horizontal component of weight of the block.

F(net) = mgsinθ

The net force on the block F(net) = mgsinθ).

The direction of motion of the block is along the direction of net force acting on the block. Since there is no frictional force between the wedge and block, the only force acting on the block along the direction of motion is mgsinθ.

(b)

From the free body diagram, the normal force n is equal to mgcosθ .

n=mgcosθ

The horizontal component of normal force on the block is equal to force

Fw=n*sin(θ) that exerted by the wall on the wedge.

Substitute mgcosθ for n in the above equation;

Fw =mg(cosθ)(sinθ)

Since, there is no friction between the wedge and the wall, there is component force acting on the wall to restrict the motion of the wedge on the surface and that force is arises from the horizontal component for normal force on the block.

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2 years ago