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irinina [24]
3 years ago
12

Cars A and B have the same mass, but Car A's speed is 15 mph, whereas Car B is moving at 60 mph. The kinetic energy

Physics
1 answer:
kupik [55]3 years ago
7 0

Answer:

16 times that of car A

Explanation:

Moving objects have kinetic energy which is calculated using the formula:

E=(1/2)mv² where m is the mass of the object and v is its velocity.

For car A, kinetic energy =1/2×m×15²

=112.5m........................................i

For car B,  the kinetic energy =1/2×m×60²

=1800m......................................ii

dividing ii by i we get

1800m/112.5m= 16.07

Therefore The kinetic energy of car B is 16.07 times that of car A

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Answer:

Labor Day Weekend--No School

9/1/2021

Hello Students!

There will be no School on Friday Sept 3 and Monday Sept 6

All centers will be closed on Friday 9/3 and Monday 9/6

School will resume on TUESDAY, Sept 7

Enjoy your long weekend!

Explanation:

Labor Day Weekend--No School

9/1/2021

Hello Students!

There will be no School on Friday Sept 3 and Monday Sept 6

All centers will be closed on Friday 9/3 and Monday 9/6

School will resume on TUESDAY, Sept 7

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3 years ago
What is intertia? Explain.​
snow_tiger [21]

Answer:

property of matter by which it continues in its existing state of rest or uniform motion in a straight line, unless that state is changed by an external force.

7 0
3 years ago
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Anyone! Help me! (:o
Gnom [1K]
You have written the answer within your question.


mass of 1kg metal is "1 kilogram"

but when you talk about it's weight
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5 0
3 years ago
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Joules constant, 4.1868 J/cal, is an equivalence relation for 4.1868 Joules of work for 1 calorie of heat delivered to a substan
Llana [10]

Answer:

The final answer is 6.1 BTU = 6.5621*103 KJ

Explanation:

1 BTU= 252 cal\\1 BTU =252 × 4.2 kJ\\6.1 BTU = 252 × 6.1×4.2 kJ                = 6562.08 kJ\\                = 6.5621 × 103 kJ\\

Hence, 6.1 BTU = 6.5621 × 103 kJ

7 0
3 years ago
A 3.0 X 10^3 grams rock swings in a circle with a diameter of 1000 cm. Given the constant speed around the circle is 17.90 mph (
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Answer:

a = 12.8 m/s^2

Explanation:

To find the centripetal acceleration you use the following formula:

a_c=\frac{v^2}{r}   (1)

v: tangential speed of the rock = 17.90mph

r: radius of the orbit = 1000cm/2 = 500cm = 0.5m

You first change the units of the tangential velocity in order to replace the values of v and r in the equation (1):

17.90mph*\frac{1609.34m}{1\ m}*\frac{1\ h}{3600\ s}=8m/s

Then, you use the equation (1):

a_c=\frac{(8m/s)^2}{5m}=12.8\frac{m}{s^2}

hence, the centripetal acceleration is 12.8 m/s^2

3 0
3 years ago
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