Compounds formed when non-metals react with metals consist of particles called ionic compound

The mass of an erlenmeyer flask is 85.135 g. after 10.00 ml of water is added to the flask, the mass of the flask and the water

BARSIC [14]

Subtracting the mass of (flask+water) from the empty flask gives:
95.023 g - 85.135 g = 9.888 grams of water
Dividing this by the given volume of 10.00 mL water gives:
9.888 grams of water / 10.00 mL of water = 0.9888 g/mL of water
Therefore, based on this sample, the density of water is 0.9888 g/mL, which is close to the usually accepted approximation of 1 g/mL.

4 0

3 years ago

HELP MEEEE ASAP!!! Answer these questions based on what you learned from the passage. You can assume any body structure comes fr

erica [24]

Answer:

1.Legs

2.Arms and hands

3.Armor

4.Skeletal

5.Carpenters

6.Brain

7.Skin

8.Blood

Explanation:

You can google dem and it will show you all the answers

4 0

4 years ago

The rate of formation of C in the reaction 2 A + B →2 C + 3 D is 2.7 mol dm−3 s −1 . State the reaction rate, and the rates of f

Zielflug [23.3K]

Answer:

Rate of reaction = $1.35mol.dm^{-3}.s^{-1}$

Rate of consumption of A = $2.7mol.dm^{-3}.s^{-1}$

Rate of consumption of B = $1.35mol.dm^{-3}.s^{-1}$

Rate of formation of D = $4.15mol.dm^{-3}.s^{-1}$

Explanation:

According to laws of mass action for the given reaction,

$Rate= -\frac{1}{2}\frac{\Delta [A]}{\Delta t}=-\frac{\Delta [B]}{\Delta t}=\frac{1}{2}\frac{\Delta [C]}{\Delta t}=\frac{1}{3}\frac{\Delta [D]}{\Delta t}$

where, $-\frac{\Delta [A]}{\Delta t}$ is rate of consumption of A, $-\frac{\Delta [B]}{\Delta t}$ is rate of consumption of B, $\frac{\Delta [C]}{\Delta t}$ is rate of formation of C and $\frac{\Delta [D]}{\Delta t}$ is rate of formation of D

Here $\frac{\Delta [C]}{\Delta t}=2.7mol.dm^{-3}.s^{-1}$

So, Rate of reaction = $(\frac{1}{2}\times 2.7mol.dm^{-3}.s^{-1})=1.35mol.dm^{-3}.s^{-1}$

Rate of formation of D = $(\frac{3}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{3}{2}\times 2.7mol.dm^{-3}.s^{-1})=4.15mol.dm^{-3}.s^{-1}$

Rate of consumption of A = $(\frac{2}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{2}{2}\times 2.7mol.dm^{-3}.s^{-1})=2.7mol.dm^{-3}.s^{-1}$

Rate of consumption of B = $(\frac{1}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{1}{2}\times 2.7mol.dm^{-3}.s^{-1})=1.35mol.dm^{-3}.s^{-1}$

3 0

3 years ago

Which of the following steps correctly converts 3 moles of fluorine to an equivalent number of particles of fluorine?

Mrrafil [7]

Multiply 3 by the atomic mass of fluorine, forgive me if I’m wrong

4 0

3 years ago

Suppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read

lapo4ka [179]

Answer:

1) 18.91 mL

2) 2.35 %

Explanation:

1. The volume of base that was required is equal to the <em>difference between the reading at the end of the titration and the reading at the beginning</em>:

V = 20.95 mL - 2.04 mL = 18.91 mL

2. The mass percent can be written as:

Mass Percent = Mass solute / Total mass * 100%

For this problem:

Mass solute = 2.28 g

Total mass = 96.92 g

We<u> input the data and calculate the mass percent</u>:

% mass = 2.28/96.92 * 100% = 2.35 %

7 0

3 years ago