Answer: -
First Ionization energy IE 1 for element X = 801
Here X is told to be in the third period.
So principal quantum number n = 3 for X.
For 1st ionization energy the expression is
IE1 = 13.6 x Z ^2 / n^2
Where Z =atomic number.
Thus Z =( n^2 x IE 1 / 13.6)^(1/2)
Z = ( 3^2 x 801 / 13.6 )^ (1/2)
= 23
Number of electrons = Z = 23
Nearest noble gas = Argon
Argon atomic number = 18
Number of extra electrons = 23 – 18 = 5
a) Electronic Configuration= [Ar] 3d34s2
We know that more the value of atomic radii, lower the force of attraction on the electrons by the nucleus and thus lower the first ionization energy.
So more the first ionization energy, less is the atomic radius.
X has more IE1 than Y.
b) So the atomic radius of X is lesser than that of Y.
c) After the first ionization, the atom is no longer electrically neutral. There is an extra proton in the atom. Due to this the remaining electrons are more strongly pulled inside than before ionization. Hence after ionization, the radii of Y decreases.
<u>Answer:</u>
<em>Adsorption is a phase conversion process that changes a mixture component from one state of matter to another is a </em><u><em>false statement.</em></u>
<em></em>
<u>Explanation:</u>
Adsorption is a process in which a solute accumulates on the surface of an adsorbent to form an atomic film.
The solute may be a gas or a liquid and the adsorbent will be a solid.
The resultant atomic film what we get is known as an adsorbate.
So molecules accumulate on the external or internal surface of the solids.
I'm assuming that you want to covert atmospheres into mmHg.
mmHg is exactly like torr: there are 760 of them in an atmosphere.
The conversion would be 760 mmHg = 1 atm
Knowing this, simply multiply 2.48 * 10^3 by 760:
2.48 * 10^3 * 760 = 1,884,800 mmHg.
But wait! I'm assuming you probably meant to write 2.48 * 10^-3, since 1,884,800 is an awfully big number.
In that case:
2.48 * 10^-3 * 760 = 1.8848 mmHg
-T.B.