Answer:
A)
,
, 
A = 1.5×
, A = 1.9×
, A=1.5×
B) 4.469
Explanation:
From Arrhenius equation

where; K = Rate of constant
A = Pre exponetial factor
= Activation Energy
R = Universal constant
T = Temperature in Kelvin
Given parameters:




taking logarithm on both sides of the equation we have;

since we have the rate of two different temperature the equation can be derived as:


= 19846.04×7.544×
= 1.497
=
= 4.469
graphite is a form of carbon in which carbon atoms are arranged in a layer.
Answer:
ΔT=-747,13°C
Explanation:
Sensible heat is<em> the amount of thermal energy that is required to change the temperature of an object</em>, the equation for calculating the heat change is given by:
Q=msΔT
where:
- Q, heat that has been absorbed or realeased by the substance [J]
- m, mass of the substance [g]
- s, specific heat capacity [J/g°C] (
- ΔT, changes in the substance temperature [°C]
To solve the problem, we clear ΔT of the equation and then replace our data:
Q=msΔT
ΔT=Q/ms
Δ
°C
<em>(Note that Q=-14900 J because there is a </em><u><em>LOST</em></u><em> of thermal energy)</em>
Thus, the change in temperature of the steel bar is -747,13°C, meaning that the temperature of the bar decreases.
Answer:
Steel and cast iron
Explanation:
They are all metal but assuming that you are finding the best material for your pan i suggest going for steel or cast iron