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White raven [17]
3 years ago
15

The balloon Spirit of Freedom, flown around the world by American Steve Fossett in 2002, contained 550,000 cubic feet of helium.

How much PΔV work was done by the balloon on the surrounding atmosphere, assuming atmospheric pressure was 1.00 atm while the balloon was being inflated?
Chemistry
1 answer:
Elodia [21]3 years ago
3 0
Assuming the balloon initially has volume of 0 when deflated, the total P(deltaV) = (1.00 atm)(550,000 ft^3) = 550,000 atm-ft^3. To convert into work units, we can first convert ft^3 to L:
(550,000 atm-ft^3)(1 m/3.28 ft)^3
= (15,586.2 atm-m^3)
Then we convert to L:
(15,586.2 atm-m^3)(1000 L/m^3)
= 15,586,200 atm-L
Then we convert to J:
(15,586,200 atm-L)(101.325 J / 1 atm-L)
= 1.579 x 10^9 J
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If the concentration of the stock (provided) Cu(NH3)42 was 0.041 M, what concentration will the Cu2 be in beaker?
kodGreya [7K]

Answer:

[Cu^{2+}]=0.041 M

Explanation:

Hello!

In this case, since the molarity of a solution is defined in terms of the moles of the solute and the volume of solution, given that the concentration of Cu(NH₃)₄²⁺ is 0.041 M, and there is only one copper atom per Cu(NH₃)₄²⁺ ion, we can compute the concentration of Cu²⁺ as shown below:

[Cu^{2+}]=0.041\frac{molCu(NH_3)_4^{2+}}{L}*\frac{1molCu^{2+}}{1molCu(NH_3)_4^{2+}} =0.041 \frac{molCu(NH_3)_4^{2+}}{L}

[Cu^{2+}]=0.041 M

Best regards!

6 0
2 years ago
An aerospace engineer is designing a rocket to have three stages. Which is
valina [46]

Answer:

<em>A not reasonable explanation for an aerospace engineer designs a rocket to have three stages is</em>:

  • <u><em>A. To simplify the design of the rocket</em></u>

Explanation:

A <em>three stages rocket</em> permits to separate the fuel compartments. The rocket must be launched with a huge amount of fuel to last the entire travel. Then the initial mass of the rocket and the fuel is considerably large.

As the rocket flies, part of the fuel is consumed and so some compartements may be separated and removed decreasing the mass of the rocket as it flies (<em>option D. </em>is a reasonable explanation), so the rocket only carries the necessary mass (<em>statement B</em>. is a reasonable explanation).

As the rocket moves away from Earth, the gravitational force decreases and, in the space, the amount of thrust needed is lesser, which the aerospace engineers take into account for the design (choice C. is a reasonable explanation).

The only <em>not reasonable explanation to design a three stage rocket</em> is to <em>simplify the design of the rocket</em>: designing a rocket with three modules each with different features, functions, and the detachment mechanisms brings lot of complex problems to solve. So, o<em>ption A. </em>is the correct answer.

4 0
3 years ago
Read 2 more answers
In performing the "STEP TEST" for 3 minutes, what was your score (your count)? *
MAXImum [283]

Answer:

81

Explanation:

8 0
3 years ago
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The density of thorium, which has the FCC structure, is 11.72 g/cm3. The atomic weight of thorium is 232 g/mol. Calculate (a) th
seropon [69]

Answer:

(a) a = 5.08x10⁻⁸ cm

(b) r = 179.6 pm  

Explanation:

(a) The lattice parameter "a" can be calculated using the following equation:

\rho = \frac{(N atoms/cell)*m}{V_{c}*N_{A}}      

<em>where ρ: is the density of Th = 11.72 g/cm³, N° atoms/cell = 4, m: is the atomic weight of Th = 232 g/mol, Vc: is the unit cell volume = a³, and </em>N_{A}<em>: is the Avogadro constant = 6.023x10²³ atoms/mol. </em>

Hence the lattice parameter is:  

a^{3} = \frac{(N atoms/cell)*m}{\rho *N_{A}} = \frac{4 atoms*232 g/mol}{11.72 g/cm^{3} *6.023 \cdot 10^{23} atoms/mol} = 1.32 \cdot 10^{-22} cm^{3}

a = \sqrt[3]{1.32 \cdot 10^{-22} cm^{3}} = 5.08 \cdot 10^{-8} cm

(b) We know that the lattice parameter of a FCC structure is:

a = \frac{4r}{\sqrt{2}}

<em>where r: is the atomic radius of Th</em>

Hence, the atomic radius of Th is:

r = \frac{a*\sqrt{2}}{4} = \frac{5.08 \cdot 10^{-8} cm*\sqrt{2}}{4} = 1.796 \cdot 10^{-8} cm = 179.6 pm    

I hope it helps you!    

4 0
3 years ago
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There are 18 protons in one atom of ³⁷Ar.

The number 37 is its <em>mass number</em> — the number of <em>protons + neutrons</em>.

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